在json_encode中傳遞 或ü

Question

我創建了一個function，它從給定的URL中獲取title並返回json。該功能由ajax調用。所有工作正常，但當任何標題包含ü或任何相關字符它返回null。我在「網絡」選項卡中回顯字符串，它顯示 而不是字符ü。

我已經嘗試瞭解決方案，我從互聯網上獲得喜歡用JSON Constant ，solution[1]，solution[2]，solution[3]許多

我試圖htmlentities後，但它返回空字符串

代碼：

$value = array(); 
$val['title'] = get_title("URL"); 
$val['link'] = $line; 
array_push($value, $val); 

function get_title($url) 
{ 

    $curl_handle = curl_init(); 
    curl_setopt($curl_handle, CURLOPT_URL, $url); 
    curl_setopt($curl_handle, CURLOPT_CONNECTTIMEOUT, 2); 
    curl_setopt($curl_handle, CURLOPT_RETURNTRANSFER, 1); 
    $query = curl_exec($curl_handle); 
    curl_close($curl_handle); 

     $normalizeChars = array(
      'Š'=>'S', 'š'=>'s', 'Ð'=>'Dj','Ž'=>'Z', 'ž'=>'z', 'À'=>'A', 'Á'=>'A', 'Â'=>'A', 'Ã'=>'A', 'Ä'=>'A', 
      'Å'=>'A', 'Æ'=>'A', 'Ç'=>'C', 'È'=>'E', 'É'=>'E', 'Ê'=>'E', 'Ë'=>'E', 'Ì'=>'I', 'Í'=>'I', 'Î'=>'I', 
      'Ï'=>'I', 'Ñ'=>'N', 'Ń'=>'N', 'Ò'=>'O', 'Ó'=>'O', 'Ô'=>'O', 'Õ'=>'O', 'Ö'=>'O', 'Ø'=>'O', 'Ù'=>'U', 'Ú'=>'U', 
      'Û'=>'U', 'Ü'=>'U', 'Ý'=>'Y', 'Þ'=>'B', 'ß'=>'Ss','à'=>'a', 'á'=>'a', 'â'=>'a', 'ã'=>'a', 'ä'=>'a', 
      'å'=>'a', 'æ'=>'a', 'ç'=>'c', 'è'=>'e', 'é'=>'e', 'ê'=>'e', 'ë'=>'e', 'ì'=>'i', 'í'=>'i', 'î'=>'i', 
      'ï'=>'i', 'ð'=>'o', 'ñ'=>'n', 'ń'=>'n', 'ò'=>'o', 'ó'=>'o', 'ô'=>'o', 'õ'=>'o', 'ö'=>'o', 'ø'=>'o', 'ù'=>'u', 
      'ú'=>'u', 'û'=>'u', 'ü'=>'u', 'ü' => 'u', 'ý'=>'y', 'ý'=>'y', 'þ'=>'b', 'ÿ'=>'y', 'ƒ'=>'f', 
      'ă'=>'a', 'î'=>'i', 'â'=>'a', 'ș'=>'s', 'ț'=>'t', 'Ă'=>'A', 'Î'=>'I', 'Â'=>'A', 'Ș'=>'S', 'Ț'=>'T', '�' => 'u', 
     ); 

    $query = trim(preg_replace('/\s+/', ' ', $query)); // supports line breaks inside <title> 
    preg_match("/\<title\>(.*)\<\/title\>/", $query, $title); // ignore case 

     $search = explode(",","ç,æ,œ,á,é,í,ó,ú,à,è,ì,ò,ù,ä,ë,ï,ö,ü,ÿ,â,ê,î,ô,û,å,ø,Ø,Å,Á,À,Â,Ä,È,É,Ê,Ë,Í,Î,Ï,Ì,Ò,Ó,Ô,Ö,Ú,Ù,Û,Ü,Ÿ,Ç,Æ,Œ,�"); 

$replace = explode(",","c,ae,oe,a,e,i,o,u,a,e,i,o,u,a,e,i,o,u,y,a,e,i,o,u,a,o,O,A,A,A,A,A,E,E,E,E,I,I,I,I,O,O,O,O,U,U,U,U,Y,C,AE,OE,u"); 

     //$title[1] = strtr($title[1], $normalizeChars); //Tried strtr function not work 
     //echo str_replace($search, $replace, $title[1]); // tried replace function not work 
     //echo $title[1]; 
     //$title[1] = htmlentities($title[1]); //works but $title[1] is null 

    if (strpos($url, '/') !== false) { 
     $url1 = explode('/', $url1); 
     $res = $url1[0] . ' | ' . $title[1]; 
    } else { 
     $res = $url1 . ' | ' . $title[1]; 
    } 
    $res = substr($res, 0, 99); 
    return $res; 
    } 
    catch(Exception $e) { echo $e; } 

} 

echo json_encode($value); 

Answer 1

嘗試使用JSON_UNESCAPED_UNICODE（僅適用於PHP> = 5.4.0）：

json_encode($value, JSON_UNESCAPED_UNICODE);