我正在用spring-boot建立一個示例項目來學習它。
具體來說,我試圖整合spring-security-oauth2模塊來保護我的休息服務。 我跟着這個示例項目,顯示了一個非常簡單的內存登錄系統:https://github.com/royclarkson/spring-rest-service-oauth
它的工作原理,這是很好的。
無論如何,當我試圖把它在我的應用程序集成,我得到以下異常:沒有發現ResourceServerTokenServices的Bean - Spring-Security-Oauth2
...
Caused by: java.lang.IllegalStateException: Could not wire ResourceServerTokenServices: please create a bean definition and mark it as @Primary.
at org.springframework.security.oauth2.config.annotation.web.configuration.ResourceServerConfiguration.resolveTokenServices(ResourceServerConfiguration.java:170) ~[spring-security-oauth2-2.0.4.RELEASE.jar:na]
at org.springframework.security.oauth2.config.annotation.web.configuration.ResourceServerConfiguration.configure(ResourceServerConfiguration.java:140) ~[spring-security-oauth2-2.0.4.RELEASE.jar:na]
at org.springframework.security.config.annotation.web.configuration.WebSecurityConfigurerAdapter.getHttp(WebSecurityConfigurerAdapter.java:199) ~[spring-security-config-3.2.5.RELEASE.jar:3.2.5.RELEASE]
at org.springframework.security.config.annotation.web.configuration.WebSecurityConfigurerAdapter.init(WebSecurityConfigurerAdapter.java:283) ~[spring-security-config-3.2.5.RELEASE.jar:3.2.5.RELEASE]
at org.springframework.security.config.annotation.web.configuration.WebSecurityConfigurerAdapter.init(WebSecurityConfigurerAdapter.java:68) ~[spring-security-config-3.2.5.RELEASE.jar:3.2.5.RELEASE]
at org.springframework.security.oauth2.config.annotation.web.configuration.ResourceServerConfiguration$$EnhancerByCGLIB$$71f30f65.init(<generated>) ~[spring-core-4.0.1.RELEASE.jar:na]
at org.springframework.security.config.annotation.AbstractConfiguredSecurityBuilder.init(AbstractConfiguredSecurityBuilder.java:367) ~[spring-security-config-3.2.5.RELEASE.jar:3.2.5.RELEASE]
at org.springframework.security.config.annotation.AbstractConfiguredSecurityBuilder.doBuild(AbstractConfiguredSecurityBuilder.java:320) ~[spring-security-config-3.2.5.RELEASE.jar:3.2.5.RELEASE]
at org.springframework.security.config.annotation.AbstractSecurityBuilder.build(AbstractSecurityBuilder.java:39) ~[spring-security-config-3.2.5.RELEASE.jar:3.2.5.RELEASE]
at org.springframework.security.config.annotation.web.configuration.WebSecurityConfiguration.springSecurityFilterChain(WebSecurityConfiguration.java:92) ~[spring-security-config-3.2.5.RELEASE.jar:3.2.5.RELEASE]
at org.springframework.security.config.annotation.web.configuration.WebSecurityConfiguration$$EnhancerByCGLIB$$373175f.CGLIB$springSecurityFilterChain$3(<generated>) ~[spring-core-4.0.1.RELEASE.jar:3.2.5.RELEASE]
at org.springframework.security.config.annotation.web.configuration.WebSecurityConfiguration$$EnhancerByCGLIB$$373175f$$FastClassByCGLIB$$ffddf00e.invoke(<generated>) ~[spring-core-4.0.1.RELEASE.jar:3.2.5.RELEASE]
at org.springframework.cglib.proxy.MethodProxy.invokeSuper(MethodProxy.java:228) ~[spring-core-4.0.1.RELEASE.jar:4.0.1.RELEASE]
at org.springframework.context.annotation.ConfigurationClassEnhancer$BeanMethodInterceptor.intercept(ConfigurationClassEnhancer.java:326) ~[spring-context-4.0.1.RELEASE.jar:4.0.1.RELEASE]
at org.springframework.security.config.annotation.web.configuration.WebSecurityConfiguration$$EnhancerByCGLIB$$373175f.springSecurityFilterChain(<generated>) ~[spring-core-4.0.1.RELEASE.jar:3.2.5.RELEASE]
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) ~[na:1.8.0]
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62) ~[na:1.8.0]
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43) ~[na:1.8.0]
at java.lang.reflect.Method.invoke(Method.java:483) ~[na:1.8.0]
at org.springframework.beans.factory.support.SimpleInstantiationStrategy.instantiate(SimpleInstantiationStrategy.java:166) ~[spring-beans-4.0.1.RELEASE.jar:4.0.1.RELEASE]
... 27 common frames omitted
據我所知,在DefaultTokenServices實施ResourceServerTokenServices應該是準備使用,而無需進一步實施(在執法機關對於本簡單的情況)。我錯了嗎?
下面的代碼片段是我的OAuth配置類:
AuthorizationServerConfiguration:
@Configuration @EnableAuthorizationServer
public class AuthorizationServerConfiguration extends AuthorizationServerConfigurerAdapter {
private TokenStore tokenStore = new InMemoryTokenStore();
@Inject
@Qualifier("authenticationManagerBean")
private AuthenticationManager authenticationManager;
@Inject
private ResourceIdProvider resourceIdProvider;
@Override
public void configure(AuthorizationServerEndpointsConfigurer endpoints) throws Exception {
endpoints
.tokenStore(tokenStore)
.authenticationManager(authenticationManager);
}
@Override
public void configure(ClientDetailsServiceConfigurer clients) throws Exception {
clients
.inMemory()
.withClient("clientapp")
.authorizedGrantTypes("password", "refresh_token")
.authorities("USER")
.scopes("read", "write")
.resourceIds(this.resourceIdProvider.getResourceId())
.secret("123456");
}
@Bean
public ResourceServerTokenServices tokenServices() {
DefaultTokenServices tokenServices = new DefaultTokenServices();
tokenServices.setSupportRefreshToken(true);
tokenServices.setTokenStore(this.tokenStore);
return tokenServices;
} }
ResourceServerConfigurationImpl:
@Configuration @EnableResourceServer
public class ResourceServerConfigurationImpl extends ResourceServerConfigurerAdapter {
@Inject
private ResourceIdProvider resourceIdProvider;
@Override
public void configure(ResourceServerSecurityConfigurer resources) {
resources.resourceId(this.resourceIdProvider.getResourceId());
}
@Override
public void configure(HttpSecurity http) throws Exception {
http
.authorizeRequests()
.antMatchers("/rest/user")
.authenticated();
} }
InMemoryWebSecurityConfiguration:
@Configuration @EnableWebSecurity
public class InMemoryWebSecurityConfiguration extends WebSecurityConfigurerAdapter {
@Override
protected void configure(AuthenticationManagerBuilder auth) throws Exception {
auth
.inMemoryAuthentication()
.withUser("roy")
.password("spring")
.roles("USER");
}
@Override
@Bean
public AuthenticationManager authenticationManagerBean() throws Exception {
return super.authenticationManagerBean();
}
}
有人能幫我搞定這個嗎?
如果你需要更多的代碼讓我知道。
在此先感謝!
錯誤消息中有一個提示(將標記服務標記爲'@ Primary')。你嘗試過嗎? – 2014-11-22 15:46:30
我沒有...'@小學'做了詭計,謝謝。我不敢相信我只是需要這個。如果您將此評論複製爲答案,我會很樂意將其標記爲正確的答案。 – andreapier 2014-11-22 15:51:13