<select><option>your gender</option></select>
<script type="text/javascript">
$('input:radio').change(function(){
var value = $("div input[type='radio']:checked").val();
if(value == "female"){
$("#item").html("<div id='items'><select style=\"float:left;margin-bottom:2px;\" name='services[]'><?php $x='<span class=\"price\">'; $y='</span>'; $sql = 'SELECT * FROM service_female'; $res =mysql_query($sql);if($res===false) {echo mysql_error();}
while($row = mysql_fetch_array($res))
{
$service_price=$row['service_price']; ?>
<option><?php echo $row['service_name'].' - '.$service_price; ?></option><?php }?></select></div><input type='button' id='add' class='img' alt=' ' value='+''>");`
我的PHP代碼:
<?php
if(isset($_POST['add'])){
if(!empty($_POST['sex']) and !empty($_POST['fname']) and !empty($_POST['lname'])){
$gender = $_POST['sex'];
$fname = $_POST['fname'];
$lname = $_POST['lname'];
$mobile = $_POST['Mnumber'];
$services = $_POST['services'];
}
}
?>
$fname
,$lname
,$mobile
- 打印,但$service
- 未定義指數:服務。幫我張貼選定值的選項值
什麼是其他方式,如果我想使用jQuery的動態添加選擇值? – Datto 2014-10-27 08:14:20
這應該是一個評論,而不是一個答案 – 2014-10-27 08:18:48