將數組劃分爲四個元素的單獨數組加上提醒

Question

我試圖將一個數組分成四個元素的單個數組，其中最後一個數組將包含提醒。例如，如果該主數組的長度屬性爲10，則將創建三個子數組 - 兩個由四個元素組成，兩個元素中的一個。

我的代碼現在看起來如下：

NSMutableArray *mainMutableArray = [NSMutableArray arrayWithObjects:@"First", @"Second", @"Third", @"Fourth", @"Fifth", @"Sixth", @"Seventh", @"Eighth", nil]; 
NSMutableArray *mutableArrayOfSubarrays = [NSMutableArray array]; 

int length = mainMutableArray.count/4; 
int location = 0; 

for (int i = 0; i < length; i++) 
{ 
    [mutableArrayOfSubarrays addObject:[mainMutableArray subarrayWithRange:NSMakeRange(location, 4)]]; 
    location += 4; 
} 

當然，這隻能當提醒等於0

任何幫助將不勝感激。

Answer 1

好了，我們開始吧：從length*4

int length = mainMutableArray.count; 

for (int location = 0; location < length; location+=4) 
{ 
    unsigned int Size=length-location; 
    if (Size>4) Size=4; 
    [mutableArrayOfSubarrays addObject:[mainMutableArray subarrayWithRange:NSMakeRange(location, Size)]]; 
} 

Answer 2

河套mainMutableArray.count得到數組的剩餘部分。

Answer 3

如果使用while循環，可以使病情描述一下你實際上是試圖做：

NSUInteger length = [mainMutableArray count]; 
NSUInteger location = 0; 
// Until the location is less than four away from the end 
while(location <= (length - 4)){ 

    [mutableArrayOfSubarrays addObject:[mainMutableArray subarrayWithRange:NSMakeRange(location, 4)]]; 
    location += 4; 
} 

// Pick up the remainder, if any 
if(location != length){ 
    [mutableArrayOfSubarrays addObject:[mainMutableArray subarrayWithRange:NSMakeRange(location, length-location)]]; 
}