如何計算輸入的整數不包括0？

Question

如何計算所有輸入的整數而不計0？

也我想要的是，如果用戶輸入0然後輸出將是「沒有數字輸入除0」，但由於我有其他輸出它也將打印。

Scanner input = new Scanner(System.in); 
    System.out.print("Enter integers, input ends with 0: "); 
    int number = input.nextInt(); 

    if(number==0){ //This prints out along with the other system.out.println 
    System.out.println("No numbers were entered except 0"); 
    } 

    while(number!=0){ 
    count++; 
    total += number; 

    if(number > 0){ 
    positive++; 
    } 
    else{ 
    negative++; 
    } 
    number = input.nextInt(); 
    } 
    average = total*1.0/count; 

    System.out.println("The number of positives is " + positive); 
    System.out.println("The number of negatives is " + negative); 
    System.out.println("The total count is " + total); 
    System.out.printf("The average is " + average); 
     } 
     } 

    OUTPUT: 
    Enter integers, input ends with 0: 1 2 -1 3 0 
    The number of positives is 3 
    The number of negatives is 1 
    The total count is 4 //mine is reading out 5 entered integers instead of 4 
    The average is 1.25` 

    //0 is the only entered number 
    Enter integers, input ends with 0: 0 
    No numbers were entered except 0 

Answer 1

你似乎在期待着什麼不同的東西你問：

The total count is 4這是反映你正在進入，值的數量不限

使用值的總和System.out.println("The total count is " + count);會給你數值（數量）。

要當你輸入任何數字（0除外），刪除多餘的輸出，你的代碼更改：

System.out.println("The number of positives is " + positive); 
System.out.println("The number of negatives is " + negative); 
System.out.println("The total count is " + total); 
System.out.printf("The average is " + average); 

到

if (count > 0) 
{ 
    System.out.println("The number of positives is " + positive); 
    System.out.println("The number of negatives is " + negative); 
    System.out.println("The total count is " + total); 
    System.out.printf("The average is " + average); 
}