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Question

下面是我應該代碼的問題：

寫一個函數showCast，需要一個電影標題，並打印出相應的演員人物的合同，文檔字符串和實施/電影中的女演員按字母順序排列。這些列必須對齊（在演員/女演員的姓名前面有20個字符（包括角色名稱）。）如果未找到該影片，則會打印出錯誤消息。

它給了什麼是應該發生在這裏

>>> showCast("Harry Potter and the Sorcerer's Stone") 

Character   Actor/Actress 

---------------------------------------- 

Albus Dumbledore Richard Harris 

Harry Potter  Daniel Radcliffe 

Hermione Granger Emma Watson 

Ron Weasley   Rupert Grint 



>>> showCast('Hairy Potter') 

No such movie found 

下面是我在同一個項目，可能會有所幫助在回答書面等功能的例子。到目前爲止，我所做的一個總結是我創建了一個名爲myIMDb的字典，其中包含電影標題的關鍵字以及另一個字典的值。在即字典中，鍵是電影的角色，而價值是演員。我已經做了它的東西。 myIMDb是記錄的全局變量。

其他功能方面，他們做的是文檔字符串

def addMovie (title, charList, actList): 
    """The function addMovie takes a title of the movie, a list of characters, 
    and a list of actors. (The order of characters and actors match one 
    another.) The function addMovie adds a pair to myIMDb. The key is the title 
    of the movie while the value is a dictionary that matches characters to 
    actors""" 

    dict2 = {} 
    for i in range (0, len(charList)): 
     dict2 [charList[i]] = actList[i] 
    myIMDb[title] = dict2 
    return myIMDb 

我已經添加了三部電影，

addMovie("Shutter Island", ["Teddy Daniels", "Chuck Aule"],["Leonardo DiCaprio, ","Mark Ruffalo"]) 

addMovie("Zombieland", ["Columbus", "Wichita"],["Jesse Eisenberg, ","Emma Stone"]) 

addMovie("O Brother, Where Art Thou", ["Everett McGill", "Pete Hogwallop"],["George Clooney, ","John Turturro"]) 



def listMovies(): 
    """returns a list of titles of all the movies in the global variable myIMDb""" 

    return (list(myIMDb.keys())) 


def findActor(title, name): 
    """ takes a movie title and a character's name and returns the 
    actor/actress that played the given character in the given movie. If the 
    given movie or the given character is notfound, it prints out an error 
    message""" 
    if title in myIMDb: 
     if name in myIMDb[title]: 
      return myIMDb[title][name] 
     else: 
      return "Error: Character not in Movie" 
    else: 
     return "Error: No movie found" 

---

現在在那裏我有麻煩

我應該編寫showCast函數，但我有很多麻煩樂。我一直在修補它一段時間，但是當我打電話給myIMDb.values（）時，一切都會返回。我似乎無法循環查看它們來創建表格。

這是我到目前爲止所提出的，但它並沒有達到我所希望的。我只是希望你們中的一個能夠引導我走向正確的方向。 （註釋掉的區域就是我之前做的，只是讓你可以看到我的思路。[print（alist）和print（alist [0]）只是爲了確認它是列表中的一個大條目，而不是分離的全部]）

def showCast(title): 

    if title in myIMDb: 
     actList=[] 
     chList=[] 
     aList = myIMDb[title] 
     print (aList) 

      """"for i in range (len(aList)): 
       if i%2==0: 
        chList.append(aList[i]) 
       else: 
        actList.append(aList[i]) 
      print(chList) 
      print(actList)"""" 

else: 
    return "Movie not Found" 

Answer 1

也許這些片段可以幫助您：

打印表行

def printRow(character, actor): 
    print(character + (20 - len(character)) * ' ' + actor)) 

排序字符

def getSortedTitleList(titleList): 
    sortedList = [] 
    characters = sorted(titleList) 
    for character in characters: 
     sortedList.append((character, titleList[character])) 
    return sortedList 

注：我改變dict.keys().sort()到sorted(dict)是兼容與Python 3

Answer 2

首先，我不認爲你應該在addMovie函數返回任何東西。只需簡單地把它添加到全局變量：

myIMDb = {} 

def addMovie (title, charList, actList): 
    global myIMDb 

    """The function addMovie takes a title of the movie, a list of characters, 
    and a list of actors. (The order of characters and actors match one 
    another.) The function addMovie adds a pair to myIMDb. The key is the title 
    of the movie while the value is a dictionary that matches characters to 
    actors""" 

    dict2 = {} 
    for i in range (0, len(charList)): 
     dict2 [charList[i]] = actList[i] 
    myIMDb[title] = dict2 

雖然我不建議經常使用全局變量，我認爲這是在這種情況下，可以原諒的：d

之後，在你的showCast功能，我倒是這樣寫：

def showCast(title): 
    if title in myIMDb: 
     actList=[] 
     chList=[] 
     movie = myIMDb[title] 
     for character, cast in movie.keys(), movie.values(): #grab the character from 
     #the keys, and cast from the values. 
       chList.append(character) 
       actList.append(cast) 

     print (chList, actList) 
    else: 
     return "Movie not Found" 

這裏是我的輸出：

['Columbus', 'Jesse Eisenberg, '] ['Wichita', 'Emma Stone'] 

它按預期工作，希望這有助於！