XMLHttpRequest不適用於Chrome

Question

我有這段代碼，簡單地將「cupom」從「0」更新爲「1」，但它並不適用於Chrome，它可以工作，任何幫助/建議都是值得歡迎的。

var req; 
function val_impressao_js(cpf) { 


if(window.XMLHttpRequest) { 
req = new XMLHttpRequest(); 
} 
else if(window.ActiveXObject) { 
req = new ActiveXObject("Microsoft.XMLHTTP"); 
} 
var url = "val_impressao.php?cpf="+cpf; 
req.open("GET", url, true); 

req.onreadystatechange = function() 
    { 
    if(req.readyState == 4 && req.status == 200) 
     { 

      window.print(); 

     } 
    } 
req.send(null); 
} 

val_impressao.php

require "arqinc/conexao.php"; 
require "arqinc/funcoesbd.php"; 

    $cpf=$_GET['cpf']; 
    $query=mysql_query("UPDATE cadcoo SET cupom=1 WHERE cpf_cadpessoafisica=$cpf AND cupom=0"); 

順便說一下，這部分心不是工作壓力太大，它不打印的頁面。

if(req.readyState == 4 && req.status == 200) 
    { 

     window.print(); 

    } 

Answer 1

我建議使用以下腳本，因爲它甚至可以與IE7和所有現代瀏覽器一起使用。

window.onload = initAll; 
var xhr = false; 

function initAll() { 
    document.getElementById("requestXML").onclick = makeRequest; 
} 

function makeRequest() { 
    if (window.XMLHttpRequest) { 
     xhr = new XMLHttpRequest(); 
    } 
    else { 
     if (window.ActiveXObject) { 
      try { 
       xhr = new ActiveXObject("Microsoft.XMLHTTP"); 
      } 
      catch (e) { } 
     } 
    } 

    if (xhr) { 
     xhr.onreadystatechange = showContents; 
     xhr.open("GET", "us-states.xml", true); 
     xhr.send(null); 
    } 
    else { 
     document.getElementById("updateArea").innerHTML = "Sorry, but I couldn't create an XMLHttpRequest"; 
    } 
    return false; 
} 

function showContents() { 
    if (xhr.readyState == 4) { 
     if (xhr.status == 200) { 
      var outMsg = xhr.responseText; 
     } 
     else { 
      var outMsg = "There was a problem with the request " + xhr.status; 
     } 
     document.getElementById("updateArea").innerHTML = outMsg; 
    } 
}