2017-04-14 71 views
-2

請幫助我在存儲在mySql數據庫中的JSP頁面的特定部分中顯示圖像,並告訴我可以將圖像存儲在任何數據類型中?使用mySql在JSP頁面上顯示圖像

+0

您通常不會將圖像存儲在表格中,而是存儲圖像的路徑/文件名。存儲實際圖像有許多原因是有問題的。這使得難以呈現到頁面是不這樣做的最大原因。 –

回答

0

網頁顯示來自URL的圖像。

您可以將圖像編碼爲data: URI,或者編寫服務器端代碼以響應某個URL來提供該圖像。

0

這個servlet添加到您的項目是這樣的:

package com.app.meservlets; 

import java.io.IOException; 

import javax.servlet.ServletException; 
import javax.servlet.annotation.MultipartConfig; 
import javax.servlet.annotation.WebServlet; 
import javax.servlet.http.HttpServlet; 
import javax.servlet.http.HttpServletRequest; 
import javax.servlet.http.HttpServletResponse; 
import javax.servlet.http.Part; 

import com.app.upload.UploadPicture; 

/** 
* 
* @author user-sqli date: 12/05/2016 17:42 
*/ 
@WebServlet(urlPatterns = "/upload", loadOnStartup = 1) 
@MultipartConfig(fileSizeThreshold = 1024 * 1024 * 2, // 2MB 
maxFileSize = 1024 * 1024 * 10, // 10MB 
maxRequestSize = 1024 * 1024 * 50) 
// 50MB 
public class ControllerUploadPicture extends HttpServlet { 

    private static final long serialVersionUID = 1L; 

    @Override 
    protected void doPost(HttpServletRequest request, 
      HttpServletResponse response) throws ServletException, IOException { 
     String appPath = request.getServletContext().getRealPath(""); 

     Part part = request.getPart("file"); 
     UploadPicture.createNewInstance().TranseferPicture(part, appPath); 

     getServletContext().getRequestDispatcher("/show.jsp").forward(request, 
       response); 
    } 

} 

,並添加這個classto項目:

package com.app.upload; 

import java.io.File; 
import java.io.IOException; 
import java.text.SimpleDateFormat; 
import java.util.Date; 
import java.util.logging.Level; 
import java.util.logging.Logger; 

import javax.servlet.http.Part; 

/** 
* 
* @author user-sqli date: 12/05/2016 17:30 
*/ 
public class UploadPicture { 
    private static final String EXTENSION = "."; 
    public static final String SAVE_DIR = "uploadImage"; 
    private static UploadPicture uploadPicture = null; 
    private static final Logger LOGGER = Logger.getLogger(UploadPicture.class 
      .getName()); 

    private UploadPicture() { 
    } 

    public String TranseferPicture(Part part, String appPath) { 
     String savePath = appPath + File.separator + SAVE_DIR; 
     File fileSaveDir = new File(savePath); 
     if (!fileSaveDir.exists()) { 
      fileSaveDir.mkdir(); 
     } 

     String fileName = new SimpleDateFormat("yyyyMMdd_HHmmss") 
       .format(new Date()); 
     String nameImage = fileName + EXTENSION + getExtensionImage(part); 
     try { 
      part.write(savePath + File.separator + nameImage); 
      LOGGER.log(Level.FINE, "Upload Picture to {0} ", savePath 
        + File.separator + nameImage); 

     } catch (IOException ex) { 
      LOGGER.log(Level.SEVERE, ex.toString(), ex); 
     } 
     return nameImage; 
    } 

    private String getExtensionImage(Part part) { 

     return part.getContentType().split("/")[1]; 
    } 

    public static UploadPicture createNewInstance() { 
     if (uploadPicture == null) { 
      uploadPicture = new UploadPicture(); 
     } 
     return uploadPicture; 
    } 
} 

在JSP這樣的:

<!DOCTYPE html > 
<html> 
<head> 
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1"> 
<title>Upload file</title> 
</head> 
<body> 
    <form method="post" action="upload" enctype="multipart/form-data"> 
     <input type="file" name="file" /><br /> <input type="submit" 
      value="Upload" /> 
    </form> 

</body> 
</html> 

和shoing此圖片:

<%@ page language="java" contentType="text/html; charset=ISO-8859-1" 
    pageEncoding="ISO-8859-1"%> 
<%@taglib uri="http://java.sun.com/jsp/jstl/core" prefix="c" %> 
<!DOCTYPE html > 
<html> 
<head> 
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1"> 
<title>Insert title here</title> 
</head> 
<body> 

uploaded image sucess. 
<%-- <img width="100px" height="100px" src="<c:url value="/uploadImage/${name}" />"> --%> 
</body> 
</html> 

此示例要求servlet> = 3.1