在Java循環中更新總數

我在每次循環運行時更新總數時遇到問題。我一直在使用值2，50和5來檢查我的工作。總數應該是：3，4.5，6.75，10.125，15.1875，但我能得到的只是第一個總數。在Java循環中更新總數

任何幫助非常感謝！謝謝！！

這裏是我的代碼：

import java.util.Scanner; 

public class Population 
{ 

public static void main(String[] args) 
{ 
    int startingOrganisms; 
    int dailyPopulation; 
    int daysMultiply; 
    double dailyTotal = 0; 
    double dailyTotal2 = 0; 
    double dailyTotal3 = 0; 

    Scanner keyboard = new Scanner(System.in); 

    System.out.println("Starting # of Organisms:"); 
    startingOrganisms = keyboard.nextInt(); 

    System.out.println("Daily Population Increase(%):"); 
    dailyPopulation = keyboard.nextInt(); 

    System.out.println("# of Days They'll Multiply:"); 
    daysMultiply = keyboard.nextInt(); 

    for (int i = 1; i<=daysMultiply; i++) 
    { 
     dailyTotal = startingOrganisms*dailyPopulation*.01; 
     dailyTotal2 = startingOrganisms + dailyTotal; 
     System.out.println("Population for day " + i + " = " + dailyTotal2); 
    } 

} 

}

來源

2014-01-28 user2970463

按你的邏輯，它看起來的效果就像你想通過改變startingOrganisms值作爲你循環的循環。

鑑於你的輸入值：2, 50 and 5，其結果是：3, 4.5, 6.75, 10.125, 15.1875，一個粗略的猜測將startingOrganisms應分配dailyTotal2

首先改變的值將改變startingOrganisms數據類型。

double startingOrganisms;

下一步將內改變其價值循環：

for (int i = 1; i <= daysMultiply; i++) { 
      dailyTotal = startingOrganisms * dailyPopulation * .01; 
      dailyTotal2 = startingOrganisms + dailyTotal; 
      startingOrganisms = dailyTotal2; 
      System.out.println("Population for day " + i + " = " + dailyTotal2); 
     }

或更好，把startingOrganisms爲您dailyTotal2計數器持有的更新值和增量：

for (int i = 1; i <= daysMultiply; i++) { 
      dailyTotal = startingOrganisms * dailyPopulation * .01; 
      startingOrganisms = startingOrganisms + dailyTotal; 
      //startingOrganisms = dailyTotal2 
      System.out.println("Population for day " + i + " = " + startingOrganisms); 
     }

上述兩種情況的結果都是您所期望的：

Starting # of Organisms: 
2 
Daily Population Increase(%): 
50 
# of Days They'll Multiply: 
5 
Population for day 1 = 3.0 
Population for day 2 = 4.5 
Population for day 3 = 6.75 
Population for day 4 = 10.125 
Population for day 5 = 15.1875

來源

2014-01-28 17:53:55 PopoFibo

謝謝！這幫助了很多！ :) – user2970463

@ user2970463不客氣 – PopoFibo

你只能得到你計算它只有一次的第一共圖大業！

你應該閱讀來自用戶的輸入，並在一個循環計算：

while(daysMultiply != -1){ // when the user wants to quit he'll enter -1, for example 
    daysMultiply = keyboard.nextInt(); 
    dailyTotal = 0; 
    dailyTotal2 = 0; 
    for (int i = 1; i<=daysMultiply; i++) 
    { 
     dailyTotal = startingOrganisms*dailyPopulation*.01; 
     dailyTotal2 = startingOrganisms + dailyTotal; 
     System.out.println("Population for day " + i + " = " + dailyTotal2); 
    } 
}

來源

2014-01-28 17:47:26 alfasin

您每天都是根據原始人口進行計算，而不是以當前人口計算。嘗試調整計算中使用目前的人口十倍的增長因素：

growth = dailyTotal*dailyPopulation*.01; 
dailyTotal dailyTotal + growth;

或在一行

dailyTotal = dailyTotal + (dailyTotal*dailyPopulation*.01);

來源

2014-01-28 17:58:48 cdkMoose

在Java循環中更新總數

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