JSON在php中搜索並刪除？

我有一個包含有值的深JSON對象會話變量$_SESSION["animals"]：再次JSON在php中搜索並刪除？

$_SESSION["animals"]='{ 
"0":{"kind":"mammal","name":"Pussy the Cat","weight":"12kg","age":"5"}, 
"1":{"kind":"mammal","name":"Roxy the Dog","weight":"25kg","age":"8"}, 
"2":{"kind":"fish","name":"Piranha the Fish","weight":"1kg","age":"1"}, 
"3":{"kind":"bird","name":"Einstein the Parrot","weight":"0.5kg","age":"4"} 
}';

例如，我想找到與「食人魚魚」的行，然後將其刪除（和json_encode它，因爲它是）。如何做到這一點？我想我需要在json_decode($_SESSION["animals"],true)搜索結果數組，並找到父鍵刪除，但我無論如何被困住。

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2010-05-25 moogeek

json_decode將把JSON對象變成一個由嵌套數組組成的PHP結構。然後你只需要循環他們和你不想要的一個unset。

<?php 
$animals = '{ 
"0":{"kind":"mammal","name":"Pussy the Cat","weight":"12kg","age":"5"}, 
"1":{"kind":"mammal","name":"Roxy the Dog","weight":"25kg","age":"8"}, 
"2":{"kind":"fish","name":"Piranha the Fish","weight":"1kg","age":"1"}, 
"3":{"kind":"bird","name":"Einstein the Parrot","weight":"0.5kg","age":"4"} 
}'; 

$animals = json_decode($animals, true); 
foreach ($animals as $key => $value) { 
    if (in_array('Piranha the Fish', $value)) { 
     unset($animals[$key]); 
    } 
} 
$animals = json_encode($animals); 
?>

來源

2010-05-25 02:20:51

謝謝！如果我不知道關鍵的名字，怎麼做？ – moogeek 2010-05-25 02:24:43

如果不知道密鑰名稱，這不是更好的解決方案。 – Sarfraz 2010-05-25 02:26:19

@moogeek：在這種情況下，你的意思是「善良」，「名稱」，「體重」和「年齡」？如果你不知道，你需要引入另一層迭代，循環'$ value'並檢查每個子值與你的字符串。如果你發現它，'unset（$ animals [$ key]）'會像上面那樣工作，然後你就可以跳出循環。我已將此代碼添加到我的答案中。 – 2010-05-25 02:38:52

您在JSON中最後一個元素的末尾添加了逗號。刪除它並json_decode將返回一個數組。簡單地循環，測試字符串，然後在找到時取消設置元素。

如果您需要最終數組重新編制索引，只需將它傳遞給array_values即可。

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2010-05-25 02:26:01 webbiedave

這個工作對我來說：

#!/usr/bin/env php 
<?php 

    function remove_json_row($json, $field, $to_find) { 

     for($i = 0, $len = count($json); $i < $len; ++$i) { 
      if ($json[$i][$field] === $to_find) { 
       array_splice($json, $i, 1); 
      } 
     } 

     return $json; 
    } 

    $animals = 
'{ 
"0":{"kind":"mammal","name":"Pussy the Cat","weight":"12kg","age":"5"}, 
"1":{"kind":"mammal","name":"Roxy the Dog","weight":"25kg","age":"8"}, 
"2":{"kind":"fish","name":"Piranha the Fish","weight":"1kg","age":"1"}, 
"3":{"kind":"bird","name":"Einstein the Parrot","weight":"0.5kg","age":"4"} 
}'; 

    $decoded = json_decode($animals, true); 

    print_r($decoded); 

    $decoded = remove_json_row($decoded, 'name', 'Piranha the Fish'); 

    print_r($decoded); 

?>

來源

2010-05-25 02:27:09

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