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我想從json中讀取對象並顯示未定義。我能否得到幫助?下面是我的代碼。而不是從數據庫中獲取名稱,它顯示未定義。我認爲問題在於我的成功功能。請幫助我。Json讀取顯示未定義的對象
<script>
$(document).ready(function(){
$.ajax({
type: 'GET',
url: 'connections/profile.php',
data: 'param=no' ,
ataType: "html",
success: function (response) {
console.log(response);
$('#basicContent').html('<h4><b>' + response.name + '</b></h4>');
},
error: function (e){
alert (e);
}
});
});
</script>
也是我的PHP從html
<?php
require_once('connect.php');
session_start();
if (!isset ($_SESSION['matric']))
{
$go="index.html";
header("Location:".$go);
}
$matric = $_SESSION['matric'];
$pass= $dbh->prepare("SELECT * FROM users WHERE matric=:matric");
$pass->bindParam(':matric', $matric);
$pass->execute();
$profile=$pass->fetch(PDO::FETCH_ASSOC);
$response = array(
'name' => $profile['name'],
'matric' => $matric,
'school' => $profile['school']
);
echo json_encode($response);
我們能看到一個例子某些被解碼爲'undefined'的JSON? –