JSON-簡單ContainerFactory通過

Question

使用解碼例如用ContainerFactory通過時，得到以下輸出：

[{DeviceType=foo, DeviceName=foo1, IPAddress=192.168.1.1, UserName=admin, Password=pw},  {DeviceType=foo, DeviceName=foo2, IPAddress=192.168.1.2, UserName=admin, Password=pw}] 

這些是當entry.getValue（）被調用所輸出的條目。

如何從這些對象中獲取數據？

例如，我將如何獲取DeviceName的值。

Map obj = (Map)parser.parse(new FileReader("example.yml"),containerFactory); 

Iterator iter = obj.entrySet().iterator(); 

//Iterator iterInner = new Iterator(); 

while(iter.hasNext()){ 
    Map.Entry entry = (Map.Entry)iter.next(); 
    System.out.println(entry.getValue());         
      } 

      //System.out.println("==toJSONString()=="); 
      //System.out.println(JSONValue.toJSONString(json)); 

     } catch (FileNotFoundException e) { 
      e.printStackTrace(); 
     } catch (IOException e) { 
      e.printStackTrace(); 
     } catch(ParseException pe){ 
      System.out.println(pe); 
      } 

---

Answer 1

嘗試找出什麼類的價值觀與System.out.println(entry.getValue().getClass())（或調試檢查它）和值實際類。從輸出看起來像List<Map<String, String>>什麼的。

Answer 2

//The innermost data is in a LinkedHashMap 
//I hope this snippet helps someone 
while(iter.hasNext) 
    { 
     LinkedList entry = (LinkedList)iter.next(); 
     LinkedList myList = new LinkedList(); 
     Map.Entry entry = (Map.Entry)iter.next(); 
     System.out.println(entry.getValue().getClass()); 
     myList = (LinkedList) (entry.getValue()); 
     System.out.println(myList); 
     Iterator iterate = myList.iterator(); 
     while (iterate.hasNext()) 
     { 
      LinkedHashMap entry2 = (LinkedHashMap)iterate.next(); 
      System.out.println(entry2.get("DeviceName")); 

     } 

}