2
我有2所列出:如何打印2個列表循環?
filtered_items_list = [src1, scr2, scr3]
filtered_items_url_list = [url1, url2, url3]
我需要打印的
src1, url1
src2, url2
src3, url3
如果我嘗試:
>>> for src, url in filtered_items_list, filtered_items_url_list:
print src, url
我得到這個錯誤:
ValueError: too many values to unpack
如果我嘗試這樣的:
>>> for src in filtered_items_list:
for url in filtered_items_url_list:
print """"src: %s; url: %s""" % (src, url)
我得到這個:
"src: src1; url: url1
"src: src1; url: url2
"src: src1; url: url3
"src: scr2; url: url1
"src: scr2; url: url2
"src: scr2; url: url3
"src: scr3; url: url1
"src: scr3; url: url2
"src: scr3; url: url3
>>>
您能否提供一個解決方案嗎?謝謝!
[izip(http://docs.python.org/library/itertools.html#itertools.izip)往往BA更好的選擇,因爲它避免了不必要的複製名單。請注意,它們都在最短列表的末尾處被切斷。如果你想使用最長的`izip_longest()`,它會爲剩餘的填充None(或其他默認值)。 – chmullig 2011-02-04 17:53:04