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我試圖從數據庫發送電子郵件。我從數據庫中收到電子郵件,並將消息發送給我從數據庫中獲得的電子郵件。如何在PHP中發送多個郵件?
我的代碼運行良好,但發送郵件時發生問題 - 只發送第一個郵件。
include("config.php");
include ("library.php");
include ("classes/class.phpmailer.php");
$sql = "select * from Table ";
$result = mysql_query($sql, $conn);
while ($row = mysql_fetch_array($result)) {
if ($row['Date_Registry'] == date("Y-m-d")){
$sql= "select * from write_message where ID='$m'";
$result = mysql_query($sql, $conn);
$row = mysql_fetch_array($result);
$email= $row['EMAIL'];
$masg = $row['Write_message'];
$Message_name = $row['Message_name'];
$email = $email;
$mail = new PHPMailer; // call the class
$mail->IsSMTP();
$mail->Host = SMTP_HOST; //Hostname of the mail server
$mail->Port = SMTP_PORT; //Port of the SMTP like to be 25, 80, 465 or 587
$mail->SMTPAuth = true; //Whether to use SMTP authentication
$mail->Username = SMTP_UNAME; //Username for SMTP authentication any valid email created in your domain
$mail->Password = SMTP_PWORD; //Password for SMTP authentication
$mail->SetFrom(SMTP_UNAME, "Helli"); //From address of the mail
// put your while loop here like below,
$mail->Subject = $Message_name; //Subject od your mail
$mail->AddAddress($email); //To address who will receive this email
}
}
難道你不需要調用send()方法嗎? – halfer 2014-11-24 09:30:34
注意:'mysql_ *'函數已被棄用,它們將在未來版本中從PHP中刪除,並且您的代碼將停止工作。您不應使用它們編寫新代碼,而應使用['mysqli_ *'或PDO](http://php.net/manual/en/mysqlinfo.api.choosing.php)。 – 2014-11-24 09:31:39