我想設置一個mysql數據庫來捕獲來自html表單的信息,但是當我測試它時,會返回下面的錯誤。該文件與數據庫位於同一臺服務器上。我的php位於錯誤之下。爲什麼我收到這個錯誤?
警告:mysql_connect()[function.mysql-connect]:拒絕用戶訪問inmoti6_ted_seminar'@'localhost'(使用password:YES)在/home/westcl5/public_html/drjseminars.com/thankyou.php上線92 無法連接:拒絕訪問用戶inmoti6_ted_seminar'@「localhost」的(使用密碼:YES)
if($_POST)
{
$con = mysql_connect("localhost","inmoti6_ted_seminar","Polarbear5");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("inmoti6_westcl5_ted_sem", $con);
$users_firstName = $_POST['first_name'];
$users_lastName = $_POST['last_name'];
$users_street = $_POST['street'];
$users_street2 = $_POST['street2'];
$users_city = $_POST['city'];
$users_state = $_POST['state'];
$users_zip = $_POST['zip'];
$users_country = $_POST['country'];
$users_email = $_POST['email'];
$users_telephone = $_POST['telephone'];
$users_practice = $_POST['practice'];
$users_firstName = mysql_real_escape_string($users_firstName);
$users_lastName = mysql_real_escape_string($users_lastName);
$users_street = mysql_real_escape_string($users_street);
$users_street2 = mysql_real_escape_string($users_street2);
$users_city = mysql_real_escape_string($users_city);
$users_state = mysql_real_escape_string($users_state);
$users_zip = mysql_real_escape_string($users_zip);
$users_country = mysql_real_escape_string($users_country);
$users_email = mysql_real_escape_string($users_email);
$users_telephone = mysql_real_escape_string($users_telephone);
$users_practice = mysql_real_escape_string($users_practice);
$query = "
INSERT INTO `westcl5_ted_sem`.`ted_seminar` (`First Name`, `Last Name`, `E-mail`, `Phone #`, `Street Address`, `Street Address 2`, `City`, `State`, `Zip Code`, `Country`, `Practice`) VALUES ('$users_firstName', '$users_lastName', '$users_email', '$users_telephone', '$users_street', '$users_street2', '$users_city', '$users_state', '$users_zip', '$users_country', '$users_practice');";
mysql_query($query);
mysql_close($con);
}
看來你的數據庫用戶沒有足夠的權限,給你的用戶所需的權限 – Adeel 2014-12-05 06:20:17
而且還注意到,'mysql_ *'功能已被棄用。停止使用它們,因爲它不再安全。看看'PDO'或'MySQLi' :) – Darren 2014-12-05 06:23:12