它是硬編碼的,但應該工作:
DECLARE @x xml
SELECT @x = (
SELECT x+''
FROM (
SELECT '%details?%id?'+CAST(id as nvarchar(max))+'%/id?%name?'+name+'%/name?' x
FROM [sample] s
UNION ALL
SELECT '%/details?'
FROM [sample] s
) as t
FOR XML PATH('')
)
SELECT CAST(REPLACE(REPLACE((CAST(@x as nvarchar(max))),'%','<'),'?','>') as xml)
In [sample]
表我:
(1,'na'),
(2,'aa'),
(3,'sd')
輸出:
<details>
<id>1</id>
<name>na</name>
<details>
<id>2</id>
<name>aa</name>
<details>
<id>3</id>
<name>sd</name>
</details>
</details>
</details>
編輯
此外,它可以用遞歸CTE來完成:
DECLARE @x xml
;WITH rec AS (
SELECT CAST((
SELECT TOP 1 id,
[name]
FROM [sample]
ORDER BY id DESC
FOR XML PATH('details')
) as xml) as d,
1 as [Level]
UNION ALL
SELECT CAST((
SELECT id,
[name],
cast(r.d as xml)
FROM [sample]
WHERE s.id = id
FOR XML PATH('details')
) as xml) as d,
r.[Level]+1
FROM [sample] s
INNER JOIN rec r
ON s.id = CAST(r.d.query('/details/id/text()') as nvarchar(max))-1
)
SELECT TOP 1 WITH TIES d
FROM rec
ORDER BY [Level] desc
相同的輸出。
爲什麼具有值2的節點ID進入內部?它等於1記錄? –
@KannanKandasamy我需要這種格式。每行都進入標籤全部進來xml。如果我有4行4即將結束。標籤在每行的值開始 –
Sathish