代碼igniter-如何將圖像保存在我的數據庫中mysql/php

Question

在我的頁面中，我創建了一個具有不同字段（如名稱，電子郵件，密碼等）的表單，現在我必須上傳圖像並存儲在我的數據庫中。任何人都會發送包含圖片上傳文件在內的所有字段的代碼。我必須多次嘗試，圖像無法在我的數據庫中上傳。 我的控制器是

function activity() 
    { 
     $this->load->library('form_validation'); 
     //field name,error message, validation rules 
     $this->form_validation->set_rules('activityid', 'Activity Id', 'trim|required'); 
     $this->form_validation->set_rules('hostid', 'Host Id', 'trim|required'); 
     $this->form_validation->set_rules('activityname', 'Activity Name', 'trim|required'); 
     $this->form_validation->set_rules('date', 'Date', 'trim|required'); 
     $this->form_validation->set_rules('venue', 'Venue', 'trim|required'); 
     $this->form_validation->set_rules('typeofactivity', 'Type of Activity', 'trim|required'); 
     $this->form_validation->set_rules('conductedby', 'Conducted By', 'trim|required'); 
     $config['upload_path'] = './asset/'; 
$config['allowed_types'] = 'gif|jpg|png|jpeg'; 
$config['max_size'] = '1000'; 
$config['max_width'] = '1024'; 
$config['max_height'] = '768'; 
$config['encrypt_name'] = TRUE; 
$this->load->library('upload', $config);  
$w = $this->upload->data(); 
     if($this->form_validation->run()==FALSE) 
     { 
      //$this->load->view('signup_form'); 
      $this->activity_reg(); 
     } 
     else 
     { 
      $this->load->model('membership_model'); 

      $query=$this->membership_model->activity(); 

      if($query) 
      { 

       $data['main_content']='signup_successful'; 
       $this->load->view('includes/templates',$data); 
      } 
      else 
      { 
       $this->load->view('activity'); 
      } 
     } 
    } 

我的模型是

function activity() 

    { 
     $w = $this->upload->data(); 
     $new_member_insert_data= array(

         'activityid'=>$this->input->post('activityid'), 
         'hostid'=>$this->input->post('hostid'), 
         'activityname'=>$this->input->post('activityname'), 
         'date'=>$this->input->post('date'), 
         'venue'=>$this->input->post('venue'), 
         'typeofactivity'=>$this->input->post('typeofactivity'), 
         'conductedby'=>$this->input->post('conductedby'), 
          'image' => $w['file_name'] 
      ); 

         $this->load->database(); 
         $insert=$this->db->insert('activity',$new_member_insert_data); 
         return $insert; 

    } 

Answer 1

使用的file_get_contents（）函數。

$image = $_FILES['YOUR_INPUT_NAME']['tmp_name']; 
$new_member_insert_data= array(
        'activityid'=>$this->input->post('activityid'), 
        'hostid'=>$this->input->post('hostid'), 
        'activityname'=>$this->input->post('activityname'), 
        'date'=>$this->input->post('date'), 
        'venue'=>$this->input->post('venue'), 
        'typeofactivity'=>$this->input->post('typeofactivity'), 
        'conductedby'=>$this->input->post('conductedby'), 
        'image' => file_get_contents($image) 
     );