我正在尋找重複在谷歌地圖表。問題是緯度略有不同,地址略有不同(但我可以告訴他們是重複的)。因此,我希望獲得所有記錄的緯度相同的小數點後4位。如何才能做到這一點?找到重複的數據庫的最大數字位數
喜歡的東西:
Select * from googlemap
having count(len latitude > 4) > 1
領域:
point_id
,entry_id
,latitude
,longitude
,address
,city
,zipcode
,state
,field_id
,icon
,supplier_id
從第一個答案的樣本數據:
'9', '51.5124', '9,557,885,908,964,1353,2145,2947'
'17', '32.7921', '17,19,94,2652'
'37', '32.7799', '37,101'
'54', '34.0953', '54,165'
'71', '42.3582', '71,2724'
'73', '25.7660', '73,125'
'100', '25.7906', '100,106'
'112', '25.7870', '112,378'
'113', '32.7114', '113,316'
'114', '25.7689', '114,140'
'129', '25.7708', '129,138,142'
'148', '25.7518', '148,155'
'156', '25.7710', '156,171'
'172', '35.6563', '172,175'
'174', '35.6559', '174,184'
'194', '48.8677', '194,261'
'195', '48.8661', '195,210,248,268'
*您可以只*檢查'ABS(g1.latitude - g2.latitude)<0.0001'(同上和經度) – alexis 2012-03-27 17:10:36