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我使用PHP提交HTML表單，我在我的表格這些領域：PHP的形式不提交，直到所有的信息輸入
- 名稱：（VARCHAR）
- 地址：（VARCHAR）
- FAX：（INT）
- PHONE：（INT）
- EMAIL：（VARCHAR）
- 加上被自身增加了一個主ID。
現在我的表單直到進入傳真字段纔會提交？有誰知道爲什麼會發生？
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" lang="en" xml:lang="en">
<body>
<?php
require_once('../../public_html/input.php');
require_once('../../public_html/nauth.php');
require_once('../../public_html/mysql.php');
if (isset($_GET['more']))
{
$more = $_GET['more'];
$new = 8;
}
if (isset($_POST['submit']))
{
$more = 4;
$new = 8;
$name = $_SESSION['username'];
$dbc = mysqli_connect(cname, chost, cpwd, cdb);
$com_name = mysqli_real_escape_string($dbc, trim($_POST['com_name']));
$com_address = mysqli_real_escape_string($dbc, trim($_POST['com_address']));
$com_phone = mysqli_real_escape_string($dbc, trim($_POST['com_phone']));
$com_fax = mysqli_real_escape_string($dbc, trim($_POST['com_fax']));
$source_id = $_POST['source'];
$com_email = mysqli_real_escape_string($dbc, trim($_POST['com_email']));
$entered_by = $name;
$query = "select * from company_customers where name='$com_name'";
$data = mysqli_query($dbc, $query);
if (mysqli_num_rows($data) == 0) //to check if the name already exists
{
$query="insert into company_customers(name,address,phone,fax,email,entered_by,source_id) values('$com_name','$com_address','$com_phone','$com_fax','$com_email','$entered_by','$source_id')";
mysqli_query($dbc, $query);
$query = "select * from company_customers where name='$com_name'";
$data = mysqli_query($dbc, $query);
$row = mysqli_fetch_array($data);
$id = $row['id']; //to add the company id in the contacts table
$i = 0;
while (!empty($_POST['name' . $i]))
{
$name = $_POST['name' . $i];
$designation = $_POST['desig' . $i];
$phone = $_POST['phone' . $i];
$query = "insert into contacts(name,designation,id,phone) values('$name','$designation','$id','$phone')";
mysqli_query($dbc, $query);
$i++;
}
mysqli_close($dbc);
echo 'Added';
require_once('option.php');
exit();
}
else echo 'company already entered';
}
else if (isset($_POST['more']))
{
$more = $_POST['count'];
$new = $more + 4;
}
?>
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="POST">
<fieldset><legend>Company Profile</legend>
<label for="com_name">Company Name:</label><input type="text" name="com_name" value="<?php if(isset($_POST['more'])) echo $_POST['com_name']; ?>"/><br />
<label for="com_address">Company Address:</label><input type="text" name="com_address" value="<?php if(isset($_POST['more'])) echo $_POST['com_address']; ?>" /><br />
<label for="com_phone">Company Phone:</label><input type="text" name="com_phone" value="<?php if(isset($_POST['more'])) echo $_POST['com_phone']; ?>" /><br />
<label for="com_fax">Company Fax:</label><input type="text" name="com_fax" value="<?php if(isset($_POST['more'])) echo $_POST['com_fax']; ?>" /><br />
<label for="com_email">Company Email:</label><input type="text" name="com_email" value="<?php if(isset($_POST['more'])) echo $_POST['email']; ?>" /><br />
<?php
$dbc = mysqli_connect(cname, chost, cpwd, cdb);
$query = "select * from source";
$data = mysqli_query($dbc, $query);
$number_row = mysqli_num_rows($data);
$source[0] = '';
$source_id[0] = '';
$i = 1;
while ($row = mysqli_fetch_array($data))
{
$source[$i] = $row['src'];
$source_id[$i] = $row['source_id'];
$i++;
}
echo '<label for="source">Source</label><select name="source">';
for ($i = 0; $i <= $number_row; $i++)
echo '<option value="' . $source_id[$i] . '">' . $source[$i] . '</option>';
echo '</select>';
?>
</fieldset>
<fieldset><legend>Company Contact</legend>
<?php
for ($i = 0; $i < $more; $i++)
{
?>
<label for="<?php echo 'name' . $i; ?>">Name:</label><input type="text" name="<?php echo 'name' . $i; ?>" value="<?php if (isset($_POST['more'])) echo $_POST['name' . $i]; ?>" />
<label for="<?php echo 'desig' . $i; ?>">Designation:</label><input type="text" name="<?php echo 'desig' . $i; ?>" value="<?php if (isset($_POST['more'])) echo $_POST['desig' . $i];?>" />
<label for="<?php echo 'phone' . $i;?>">Phone:</label><input type="text" name="<?php echo 'phone' . $i;?>" value="<?php if (isset($_POST['more'])) echo $_POST['phone' . $i]; ?>" /><br />
<?php
}
?>
<input type="hidden" name="count" value="<?php echo $new; ?>" />
<input type="submit" name="more" value="more" />
</fieldset>
<input type="submit" name="submit" value="ADD" />
</form>
</body>
</html>
你能發佈你的表單的HTML版本和處理提交的php函數嗎？ – smcphill
nope。除非我們看到一些代碼，否則我們不會有任你是否複製/粘貼了包含（客戶端/ JS）驗證的代碼？ – thescientist
告訴我們要知道答案的代碼 – Kumar