如何獲取服務器上文件的實際名稱？

Question

我試圖像一個URL來獲取文件的名稱：

http://www.example.com/to/the/path/File.txt

在java中的：

public String getFileName(URL url) {  
    String filename = url.getFile();  
    return filename.substring(filename.lastIndexOf('/')+1); 
} 

但是如何從一個文件的實際文件名：

https://docs.google.com/uc?export=download&id=0BwScoO2FIDnQQlF2cHVLbHBjQzg
（它是一個公共共享我的谷歌驅動器上的文件。）

我經常看到，當我把這類在我的web瀏覽器的地址欄中的URL，它能夠識別該文件的名稱，並保存其實際的文件名稱。在java中可能嗎？

謝謝！

Answer 1

好吧，簡單地說，你需要調查究竟是什麼引起的。獲取CURL，看看發生了什麼事情：

curl -D - -o /dev/null -L "https://docs.google.com/uc?export=download&id=0BwScoO2FIDnQQlF2cHVLbHBjQzg" 

，會給你這樣的：

Content-Type: text/html; charset=UTF-8 
    Cache-Control: no-cache, no-store, max-age=0, must-revalidate 
    Pragma: no-cache 
    Expires: Fri, 01 Jan 1990 00:00:00 GMT 
    Date: Fri, 03 Apr 2015 17:42:47 GMT 
    Location: https://doc-0c-8k-docs.googleusercontent.com/docs/securesc/ha0ro937gcuc7l7deffksulhg5h7mbp1/m2vr72uv54vrhd59tvsm5ellda89n0s6/1428076800000/17869486772410674836/*/0BwScoO2FIDnQQlF2cHVLbHBjQzg?e=download 
    Set-Cookie: NID=67=fxFK6wjqCslAMuLajOnHKWYlkVAJDG6gMzoQnsDZI2wkd5QlP7meP8tDQJEQk9veY0UUOtSZWAjM_JbHAOMcJavkHU2B6-VDUo3jRpBQSm0moWVmN689L-I1vKgGJoVK;Domain=.google.com;Path=/;Expires=Sat, 03-Oct-2015 17:42:47 GMT;HttpOnly 
    P3P: CP="This is not a P3P policy! See http://www.google.com/support/accounts/bin/answer.py?hl=en&answer=151657 for more info." 
    X-Content-Type-Options: nosniff 
    X-Frame-Options: SAMEORIGIN 
    X-XSS-Protection: 1; mode=block 
    Server: GSE 
    Alternate-Protocol: 443:quic,p=0.5 
    Accept-Ranges: none 
    Vary: Accept-Encoding 
    Transfer-Encoding: chunked 

    HTTP/1.1 200 OK 
    Access-Control-Allow-Origin: * 
    Access-Control-Allow-Credentials: false 
    Access-Control-Allow-Headers: Accept, Accept-Language, Authorization, Cache-Control, Content-Disposition, Content-Encoding, Content-Language, Content-Length, Content-MD5, Content-Range, Content-Type, Date, GData-Version, Host, If-Match, If-Modified-Since, If-None-Match, If-Unmodified-Since, Origin, OriginToken, Pragma, Range, Slug, Transfer-Encoding, X-ClientDetails, X-GData-Client, X-GData-Key, X-Goog-AuthUser, X-Goog-PageId, X-Goog-Encode-Response-If-Executable, X-Goog-Correlation-Id, X-Goog-Request-Info, X-Goog-Experiments, x-goog-iam-role, x-goog-iam-authorization-token, X-Goog-Spatula, X-Goog-Upload-Command, X-Goog-Upload-Content-Disposition, X-Goog-Upload-Content-Length, X-Goog-Upload-Content-Type, X-Goog-Upload-File-Name, X-Goog-Upload-Offset, X-Goog-Upload-Protocol, X-Goog-Visitor-Id, X-HTTP-Method-Override, X-JavaScript-User-Agent, X-Pan-Versionid, X-Origin, X-Referer, X-Upload-Content-Length, X-Upload-Content-Type, X-Use-HTTP-Status-Code-Override, X-YouTube-VVT, X-YouTube-Page-CL, X-YouTube-Page-Timestamp 
    Access-Control-Allow-Methods: GET,OPTIONS 
    Content-Type: application/zip 
    Content-Disposition: attachment;filename="All.zip";filename*=UTF-8''All.zip 
    Date: Fri, 03 Apr 2015 17:42:47 GMT 
    Expires: Fri, 03 Apr 2015 17:42:47 GMT 
    Cache-Control: private, max-age=0 
    X-Goog-Hash: crc32c=yKvC2Q== 
    Transfer-Encoding: chunked 
    Server: UploadServer ("Built on Mar 27 2015 13:04:19 (1427486659)") 
    Alternate-Protocol: 443:quic,p=0.5 

在這裏，你可以看到：

• 有重定向到另一個URL https://doc-0c-8k-docs.googleusercontent.com/docs/securesc/ha0ro937gcuc7l7deffksulhg5h7mbp1/m2vr72uv54vrhd59tvsm5ellda89n0s6/1428076800000/17869486772410674836/ */0BwScoO2FIDnQQlF2cHVLbHBjQzg？e =下載

• 該URL處的文檔將作爲附件返回，因此您需要檢查標題的內容處置：的值，該名稱將爲您提供名稱filename =「All.zip」。

所以，現在你想自動完成這個，也許 - 和this link會幫助你。

快樂學習！

Answer 2

您可以創建File對象類並調用getName（）方法來獲取文件的絕對名稱。

File file = new File("http://www.example.com/to/the/path/File.txt"); 
    System.out.println(file.getName()); 

如果你沒有文件和谷歌文件路徑的絕對路徑，你不能獲取文件名不是絕對的文件路徑。