在創建表時創建成員表中的條目並且不會再創建php pdo

Question

This答案在創建數據庫時提供用戶和密碼。我只想知道這是否是我正在尋找的答案。

我在php pdo中創建了幾個表格，並且一個表格是專門用於成員的。在這張表中，我想創建有限數量的用戶並已經指定（不需要註冊）。我想這樣做，當數據庫創建時，成員表將被填充，並且不會再次填充以避免重複輸入。

我有他的用戶權限的答案，如果我有這個功能，它將是一個很好的功能，但我不熟悉它，但不幸的是，他沒有提供任何解釋如何做到這一點。我想知道是否有其他人可以提供關於我的問題的教程或建議。任何建議，非常感謝。

UPDATE：

<?php 
global $dbh; 
$dbname = 'memberdb'; 
$member = "member"; 
    try { 
     $dbh = new PDO("mysql:host=localhost", "root", ""); 
     $dbh->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); 
     $dbname = "`".str_replace("`","``",$dbname)."`"; 
     $dbh->query("CREATE DATABASE IF NOT EXISTS $dbname"); 
     $dbh->query("use $dbname"); 
    $dbh->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); 
    $sql ="CREATE TABLE IF NOT EXISTS $member ( 
     mem_id int(40) NOT NULL AUTO_INCREMENT PRIMARY KEY, 
     username VARCHAR(40) NOT NULL, 
     password VARCHAR(40) NOT NULL);" ; 
     $dbh->exec($sql); 


    } catch(PDOException $e) { 

} 
?> 

這是我創造我的數據庫和表的config.php：

<?php 
include('config.php'); 
session_start(); 


$stmt = $dbh->prepare("SELECT * FROM member") ; 
    $stmt->execute(); 
    $count = $stmt -> rowCount(); 
    if($count == 00){ 
     $stmt = $dbh->prepare("INSERT INTO member (username, password) VALUES (?,?)")or die($db->errorInfo()); 
     $stmt->bindValue(1,"admin1",PDO::PARAM_STR); 
     $stmt->bindValue(2,"password1",PDO::PARAM_STR); 
     $stmt->execute(); 
     $stmt->bindValue(1,"admin2",PDO::PARAM_STR); 
     $stmt->bindValue(2,"password2",PDO::PARAM_STR); 
     $stmt->execute(); 
     $stmt->bindValue(1,"admin3",PDO::PARAM_STR); 
     $stmt->bindValue(2,"password3",PDO::PARAM_STR); 
     $stmt->execute(); 
    } 
function ChangePassword() { 
    global $dbh; 
    $oldpass = trim($_POST['oldpass']); 
     $newpass = trim($_POST['newpass']); 
     $cpass = trim($_POST['cpass']); 
     $user = $_SESSION['login_user']; 
if(!empty($_POST['oldpass'])){ 
     $oldpass = trim($_POST['oldpass']); 
     $newpass = trim($_POST['newpass']); 
     $cpass = trim($_POST['cpass']); 
     $user = $_SESSION['login_user']; 
     $stmt = $dbh->prepare("SELECT * FROM member WHERE username = ? ") ; 
     $stmt->bindValue(1,$user); 
     $stmt->execute(); 
     $selected_row = $stmt->fetch(PDO::FETCH_ASSOC); 
     echo $selected_row['mem_id']; 
     echo $cpass; 
     if($selected_row['password']===$oldpass){ 
      if($newpass===$cpass){ 
      $oldpass = trim($_POST['oldpass']); 
     $newpass = trim($_POST['newpass']); 
     $cpass = trim($_POST['cpass']); 
     $user = $_SESSION['login_user']; 
      $stmt = $dbh->prepare("UPDATE member SET password=:NEWPASSWORD WHERE mem_id=:ID"); 
      $selected_row = $stmt->fetch(PDO::FETCH_ASSOC); 
      $stmt->bindValue(':ID',$selected_row['mem_id'],PDO::PARAM_STR); 
      $stmt->bindValue(':NEWPASSWORD',$cpass,PDO::PARAM_STR); 
      if($stmt->execute()){ 
       echo "<script type='text/javascript'>alert('Password Changed'); 

       </script>"; 
       exit; 
       }else{ 
        echo "<script type='text/javascript'>alert('Password not Changed'); 
        window.location='dashboard.php'; 
        </script>"; 
        exit; 
       } 

      }else{ 
       echo "<script type='text/javascript'>alert('Password new password and confirm password does not match'); 
       window.location='dashboard.php'; 
       </script>"; 
       exit; 
      } 
     }else{ 
      echo "<script type='text/javascript'>alert('Wrong old password'); 
      window.location='dashboard.php'; 
      </script>"; 
      exit; 
     } 
}else{ 
    echo "<script type='text/javascript'>alert('Empty old password'); 
    window.location='dashboard.php'; 
    </script>"; 
    exit; 
} 
} 
?> 

這是我創建條目渣滓文件，但changepassword不工作。當我運行它時，它會跳轉到if($stmt->execute())並提示password changed，但在數據庫中它不會更改。

Answer 1

當$stmt->execute()返回true時，並不表示密碼已更新。這僅表示查詢正確執行。

爲了找出你需要檢查多少行UPDATE查詢的影響，使用rowCount：

if($stmt->execute()){ 
    if($stmt -> rowCount() >0){ 
     echo "<script type='text/javascript'>alert('Password Changed');</script>"; 
     exit; 
    }else{ 
     echo "<script type='text/javascript'>alert('Password not Changed'); 
     window.location='dashboard.php'; 
     </script>"; 
     exit; 
    } 
}else{ 
    echo "<script type='text/javascript'>alert('Error Occured');</script>"; 
    var_dump($stmt->error()); 
    exit; 
}