使用成員函數作爲STL比較函數的bind（）

有人能告訴我爲什麼下面不會編譯？使用成員函數作爲STL比較函數的bind（）

#include "a.h" 
#include <list> 
#include <algorithm> 
#include <tr1/functional> 

using namespace std; 

class B { 
    public: 
    B() { 
     list< A* > aList; 
     A* a = new A(); 
     lower_bound(aList.begin(), aList.end(), a, tr1::bind(&B::aComp, tr1::placeholders::_1, tr1::placeholders::_2)); 
    } 
    private: 
    bool aComp(A* a1, A* a2); 
};

編譯輸出：

In file included from c:\qt\2010.04\mingw\bin\../lib/gcc/mingw32/4.4.0/include/c++/tr1/functional:56, 
from ..\bindTest\/b.h:4, 
from ..\bindTest\b.cpp:1: 
c:\qt\2010.04\mingw\bin\../lib/gcc/mingw32/4.4.0/include/c++/tr1_impl/functional: In member function 'typename std::tr1::result_of<_Functor(typename std::tr1::result_of<std::tr1::_Mu<_Bound_args, std::tr1::is_bind_expression::value, (std::tr1::is_placeholder::value > 0)>(_Bound_args, std::tr1::tuple<_UElements ...>)>::type ...)>::type std::tr1::_Bind<_Functor(_Bound_args ...)>::__call(const std::tr1::tuple<_UElements ...>&, std::tr1::_Index_tuple<_Indexes ...>) [with _Args = A*&, A* const&, int ..._Indexes = 0, 1, _Functor = std::tr1::_Mem_fn<bool (B::*)(A*, A*)>, _Bound_args = std::tr1::_Placeholder<1>, std::tr1::_Placeholder<2>]': 
c:\qt\2010.04\mingw\bin\../lib/gcc/mingw32/4.4.0/include/c++/tr1_impl/functional:1191: instantiated from 'typename std::tr1::result_of<_Functor(typename std::tr1::result_of<std::tr1::_Mu<_Bound_args, std::tr1::is_bind_expression::value, (std::tr1::is_placeholder::value > 0)>(_Bound_args, std::tr1::tuple<_UElements ...>)>::type ...)>::type std::tr1::_Bind<_Functor(_Bound_args ...)>::operator()(_Args& ...) [with _Args = A*, A* const, _Functor = std::tr1::_Mem_fn<bool (B::*)(A*, A*)>, _Bound_args = std::tr1::_Placeholder<1>, std::tr1::_Placeholder<2>]' 
c:\qt\2010.04\mingw\bin\../lib/gcc/mingw32/4.4.0/include/c++/bits/stl_algo.h:2495: instantiated from '_FIter std::lower_bound(_FIter, _FIter, const _Tp&, _Compare) [with _FIter = std::_List_iterator<A*>, _Tp = A*, _Compare = std::tr1::_Bind<std::tr1::_Mem_fn<bool (B::*)(A*, A*)>(std::tr1::_Placeholder<1>, std::tr1::_Placeholder<2>)>]' 
..\bindTest\/b.h:13: instantiated from here 
c:\qt\2010.04\mingw\bin\../lib/gcc/mingw32/4.4.0/include/c++/tr1_impl/functional:1137: error: no match for call to '(std::tr1::_Mem_fn<bool (B::*)(A*, A*)>) (A*&, A* const&)' 
c:\qt\2010.04\mingw\bin\../lib/gcc/mingw32/4.4.0/include/c++/tr1_impl/functional:546: note: candidates are: _Res std::tr1::_Mem_fn<_Res (_Class::*)(_ArgTypes ...)>::operator()(_Class&, _ArgTypes ...) const [with _Res = bool, _Class = B, _ArgTypes = A*, A*] 
c:\qt\2010.04\mingw\bin\../lib/gcc/mingw32/4.4.0/include/c++/tr1_impl/functional:551: note: _Res std::tr1::_Mem_fn<_Res (_Class::*)(_ArgTypes ...)>::operator()(_Class*, _ArgTypes ...) const [with _Res = bool, _Class = B, _ArgTypes = A*, A*]

來源

2010-07-21 zoo

最長的錯誤行有史以來** **。 oO – ereOn 2010-07-21 15:11:37

@ereOn：不幸的是錯誤 - 這只是一個頁面而已。我生成了一個長度超過四頁的頁面（並且包含一個單一的模板實例，當您擴展出所有模板參數時，這個實例的類型在頁面上有一個名稱）。 – 2010-07-21 15:31:55

aComp是B的非靜態成員函數，所以你需要綁定到this指針，以及：

tr1::bind(&B::aComp, this, tr1::placeholders::_1, tr1::placeholders::_2)

來源

2010-07-21 15:12:16

使用成員函數作爲STL比較函數的bind（）

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