2013-07-09 53 views
2

我在GAE中實現了SOAP Web服務。由於GAE不支持JAX-WS我選擇去this way,這基本上是從一個servlet構建soap請求和響應。在servlet實現的SOAP Web服務中返回wsdl

一切工作正常,但我怎樣才能實現返回http://myurl/MyService?wsdl的wsdl描述?

我想我必須實現我的servlet的GET方法,但是如何?

回答

2

我附上了一個工作實施。請注意,它基於Servlet 3.0規範。如果您使用2.5,註釋將不起作用。

import java.io.FileInputStream; 
import java.io.IOException; 
import java.util.Enumeration; 

import javax.servlet.ServletException; 
import javax.servlet.annotation.WebServlet; 
import javax.servlet.http.HttpServlet; 
import javax.servlet.http.HttpServletRequest; 
import javax.servlet.http.HttpServletResponse; 

@WebServlet(name="MyWSServlet", urlPatterns={"/MyService"}) 
public class MyWSServlet extends HttpServlet { 

    private static final long serialVersionUID = 3605874163075522777L; 

    @Override 
    protected void doGet(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException { 
     boolean requestForWSDL = false; 
     Enumeration<String> params = req.getParameterNames(); 
     while (params.hasMoreElements()) { 
      if ("wsdl".equalsIgnoreCase(params.nextElement())) { 
       requestForWSDL = true; 
      } 
     } 
     if (requestForWSDL) { 
      FileInputStream wsdlInputStream = new FileInputStream(req.getServletContext().getRealPath("/wsdl/TemperatureService.wsdl")); 
      byte[] buffer = new byte[1024]; 
      resp.setContentType("application/xml"); 
      int bytesRead = 0; 
      while ((bytesRead = wsdlInputStream.read(buffer)) != -1) { 
       resp.getOutputStream().write(buffer, 0, bytesRead); 

      } 
      wsdlInputStream.close(); 
      resp.getOutputStream().flush(); 
     } 
    } 
} 
+0

謝謝@Rama,我已經擁有它了。我只是努力CharacterEncoding和PrintWriter在這裏討論http://stackoverflow.com/questions/9230775/how-to-make-simplest-servlet-filter-respect-setted-character-encoding,直到我切換到OutputStream像在你的榜樣。謝謝 – eskalera