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我很確定我有這個想法,但我有3個數組,我初始化不在主要方法,但顯然我不能調用這些數組時調用方法的主要方法,所以我的問題是,用我下面的代碼有沒有辦法讓我的方法來識別它們?或者我能做些什麼來初始化主要方法中的所有內容?我需要有一個閱讀方法一級方法平均方法和輸出方法。嘗試調用main方法中的變量在其他方法中初始化的方法
import java.util.*;
import java.io.*;
public class Proj5 {
public static void main(String[] args)throws IOException{
int lines=0;
int [] quizKey = {1,1,2,2,1,1,3,2,4,1,3,5,4,1,2};
String [] userAnswers = new String[100];
int [][] userIndividualAnswers = new int[quizKey.length][userAnswers.length];
int [] numCorrect = new int[quizKey.length];
readInText(lines, userAnswers, quizKey);
displayOutput(lines, percentCorrect, quizKey, userAnswers, userAnswersInt, numCorrect, grade);
}//end main
public static void readInText(int lines, String userAnswers[], int quizKey[])throws IOException{
Scanner inFile = new Scanner(new File("QuizScores.txt"));
while(inFile.hasNext()){
String line = inFile.nextLine();
String[] tokens = line.split(",");
userAnswers[lines] = tokens[1];
lines ++;
}// end while loop
int[][] userAnswersInt = new int[quizKey.length][lines];
char[] grade = new char[lines];
double[] percentCorrect = new double[lines];
}// end readInText
public static void gradeSingleQuiz(String tokens[], int lines, int quizKey[], String userAnswers[], int numCorrect[], int userAnswersInt[][], char grade[], double percentCorrect[]){
for (int j=0; j<=lines; j++){
numCorrect[j]=0;
for (int n=0; n<=quizKey.length; n++){
userAnswersInt[n][j] = Integer.parseInt(userAnswers[n]);
if(userAnswersInt[n][j]==(quizKey[n])){
numCorrect[j]++;
}
if(numCorrect[j]>=14)
grade[j]='A';
else if((numCorrect[j]>=12)&&(numCorrect[j]<14))
grade[j]='B';
else if((numCorrect[j]>=11)&&(numCorrect[j]<12))
grade[j]='C';
else if ((numCorrect[j]>=9)&&(numCorrect[j]<11))
grade[j]='D';
else
grade[j]='F';
percentCorrect[j] = numCorrect[j]/quizKey.length;
}//end for loop
}//end for loop
for(int i=0; i<lines; i++){
System.out.println(tokens[0] + " " + numCorrect[i] + " " +
(percentCorrect[i]) + " " + grade[i]);
}
}// end gradeSingleQuiz
public static void averageScore(int lines, double percentCorrect[]){
for(int d=0; d<=lines; d++){
System.out.println("Average: " + percentCorrect[d]);
}//end for loop
}// end averageScore
public static void displayOutput(String tokens[], int lines, int quizKey[], String userAnswers[], int numCorrect[], int userAnswersInt[][], char grade[], double percentCorrect[]){
System.out.println("Student ID # Correct %Correct Grade");
gradeSingleQuiz(tokens, lines, quizKey, userAnswers, numCorrect, userAnswersInt, grade, percentCorrect);
}// end display output
}//end class
此外,這似乎很像功課,這就是爲什麼我試圖不要給你一個完全具體的答案。不過,我希望這足以讓你解決你的問題!祝你好運! – krishnakid 2013-03-15 03:30:02
因此,如果只是返回每個數組,它會在我調用該方法時識別它?是的,這是家庭作業對不起,我只是卡住了,不能看到我需要的東西。 – 2013-03-15 03:40:59