時髦雖然循環/時髦的語法錯誤Python 2.7

Question

我試過幾件事情來解決這個循環，它只是不會工作。至於現在它給了我一個語法錯誤，突出顯示第一個打印語句中的yes後面的引號......我沒有看到任何錯誤嗎？

Ycount = 0 
Ncount = 0 
Valid = ["Y","y"] 
InValid = ["N","n"] 
Quit = ["Q","q"] 
Uinp = "" 

while Uinp != "Q": 
    Uinp = raw_input("Did you answer Y or N to the question(enter Q to quit)? ") 
    if Uinp in Valid: 
     Ycount = Ycount + 1 
     print "You have answered yes" ,Ycount, "times" 
     print "You have answered no" ,Ncount, "times" 
    elif Uinp in InValid: 
     Ncount = Ncount + 1 
     print "You have answered yes" ,Ycount, "times" 
     print "You have answered no" ,Ncount, "times" 
    elif Uinp in Quit: 
     break 

Answer 1

編輯：你的問題的解決方案是由森美阿魯斯給出的 - 我提出的觀點僅僅是良好的Python的做法。

打印出他們與各種類型的字符串（在你的情況，字符串，然後INT，其次是字符串中的首選，Python的方式，是使用上的字符串操作.format(*args)功能。在這種情況下，你可以使用

print ("You have answered yes {0} times".format(Ycount)) 

如果你要打印出多個參數，第一個是由{0}引用，接下來通過「{1}」，等等。

雖然它也適用於使用C-esque %運營商格式化蜇（例如You have answered yes %d times " % Ycount，這我不是首選。

嘗試使用大括號語法。在大型項目中，它將顯着提高代碼速度（計算並打印一個字符串，而不是打印三個字符串），而且通常對Python更具慣用性。

Answer 2

我已經在python 2下運行了你的代碼，它按預期工作。

在python3但是，也有讓你運行它需要做一些改變：

不再支持print "something"，你需要使用 print ("something")

和raw_input更名爲input

Ycount = 0 
Ncount = 0 
Valid = ["Y","y"] 
InValid = ["N","n"] 
Quit = ["Q","q"] 
Uinp = "" 

while Uinp != "Q": 
    Uinp = input("Did you answer Y or N to the question(enter Q to quit)? ") 
    if Uinp in Valid: 
     Ycount = Ycount + 1 
     print ("You have answered yes" ,Ycount, "times") 
     print ("You have answered no" ,Ncount, "times") 
    elif Uinp in InValid: 
     Ncount = Ncount + 1 
     print ("You have answered yes" ,Ycount, "times") 
     print ("You have answered no" ,Ncount, "times") 
    elif Uinp in Quit: 
     break