我有兩個表,a_users和a_student_tutors。我基本上希望加入他們的身份證號碼兩個。但是,我試圖找出不在a_student_tutors中的成員並顯示他們。試圖顯示JOIN mysql中沒有任何表格的結果
這裏編碼例如
$queryone = "SELECT * from a_users JOIN a_student_tutors on a_users.id=a_student_tutors.mem_id ";
$resultone = mysql_query($queryone);
while ($row=mysql_fetch_assoc($resultone)){
$member = $row['mem_id'];
$query = "SELECT * FROM a_users where id != '$member'";
echo $query;
}
$result = mysql_query($query);
$numrows = mysql_num_rows($result);
while ($row=mysql_fetch_assoc($result)){
echo "<tr>
<td><a href=\"members-edit.php?id=".$row['id']."\">".$row['name']."</a></td>
<td>".$row['username']."</td>
<td>".$row['address']." | ".$row['city']." | ".$row['postcode']."</td>
<td ><input type=\"checkbox\" name=\"checkbox[]\" id=\"checkbox[]\" value=\"".$row['id']."\" /></td>
</tr>";
}
究竟什麼是你的問題? –