的Javascript：延遲提交不正確

Question

https://jsfiddle.net/z1ctm0hd/

的jsfiddle產生錯誤的奇怪的名單（PIC http://i.share.pho.to/7e8051a3_l.png）的工作，但是，自動提交正在我的網頁上，但沒有請求的延遲。任何人都可以獲得幫助。

<form id='formBlokUziv' action='' method='post'> 

    <div class='onoffswitch'> 
     <input type='checkbox' name='onoffswitch1' value='1' onchange='setTimeout(document.getElementById("formBlokUziv").submit(), 5000);' class='onoffswitch-checkbox' id='myonoffswitch1' > 
    <label class='onoffswitch-label' for='myonoffswitch1'> 
     <span class='onoffswitch-inner'></span> 
     <span class='onoffswitch-switch'></span> 
    </label> 
    </div> 

    <div class='onoffswitch'> 
     <input type='checkbox' name='onoffswitch2' value='2' onchange='setTimeout(document.getElementById("formBlokUziv").submit(), 5000);' class='onoffswitch-checkbox' id='myonoffswitch2' > 
    <label class='onoffswitch-label' for='myonoffswitch2'> 
     <span class='onoffswitch-inner'></span> 
     <span class='onoffswitch-switch'></span> 
    </label> 
    </div> 

    <div class='onoffswitch'> 
     <input type='checkbox' name='onoffswitch3' value='3' onchange='setTimeout(document.getElementById("formBlokUziv").submit(), 5000);' class='onoffswitch-checkbox' id='myonoffswitch3' > 
    <label class='onoffswitch-label' for='myonoffswitch3'> 
     <span class='onoffswitch-inner'></span> 
     <span class='onoffswitch-switch'></span> 
    </label> 
    </div> 

</form> 

Answer 1

輸入的命令如在setTimeout調用的第一個參數將被立即執行。將每個超時放入一個函數中，並在指定的超時後運行。類似 -

setTimeout(function() { document.getElementById("formBlokUziv").submit() }, 5000);