我使用python腳本在Chrome中登錄到gmail,但是在點擊下一步代碼返回錯誤之後,任何人都可以請幫助我什麼是錯誤的,我是python新手。下面是我使用的代碼。如何使用python在窗口中使用chrome登錄到gmail
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.support.select import Select
import threading
import os,time,csv,datetime
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import Select
a = webdriver.Chrome()
a.get("https://accounts.google.com/")
user = a.find_element_by_id("Email")
user.send_keys('[email protected]')
login = a.find_element_by_id("next")
login.click()
pwd = WebDriverWait(a, 10).until(EC.presence_of_element_located((By.ID, "Passwd")))
pwd.send_keys('p######')
login = a.find_element_by_id("signIn")
login.click()
clk = WebDriverWait(a, 10).until(EC.presence_of_element_located((By.LINK_TEXT, 'myaccount')))
clk.click()
logout = WebDriverWait(a, 10).until(EC.presence_of_element_located((By.ID, "gb_71")))
logout.click()
下面是錯誤:
回溯(最近通話最後一個): 文件 「C:\用戶\ mapraveenkumar \文檔\ Python的\ gmail.py」,第20行,在 CLK = WebDriverWait(a,10).until(EC.presence_of_element_located((By.LINK_TEXT,'myaccount'))) 文件「C:\ Users \ mapraveenkumar \ AppData \ Local \ Programs \ Python \ Python36-32 \ lib \ site- package \ selenium \ webdriver \ support \ wait.py「,第80行,直到 raise TimeoutException(message,screen,stacktrace) selenium.common.exceptions.TimeoutException:消息:
請添加錯誤.. – franklinsijo
這是錯誤:文件 「C:/Users/mapraveenkumar/Documents/Python/gmail.py」,第12行,在 PWD = a.find_element_by_css_selector(「#Passwd」) 文件「C:\ Users \ mapraveenkumar \ AppData \ Local \ Programs \ Python \ Python36-32 \ lib \ site-packages \ selenium \ webdriver \ remote \ webdriver.py」,第437行,在find_element_by_css_selector中返回self.find_element(by = By.CSS_SELECTOR,value = css_selector) –
用錯誤更新帖子,不在註釋中。並且您發佈的錯誤代碼不匹配 – franklinsijo