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我試圖從self.mapView.gps.currentPoint
中提取x和y座標,我該怎麼做?如何獲得座標?
這是我迄今所做的:
NSLog(@"Location1 : %@", self.mapView.gps.currentPoint);
結果:
Location1 : AGSMutablePoint: x = 29841.008687, y = 40101.841687, spatial reference:
[AGSSpatialReference: wkid = 0, wkt = "PROJCS["SVY21",
GEOGCS[
"SVY21[WGS84]",
DATUM[
"D_WGS_1984",
SPHEROID["WGS_1984",6378137.0,298.257223563]
],
PRIMEM["Greenwich",0.0],
UNIT["Degree",0.0174532925199433]
],
PROJECTION["Transverse_Mercator"],
PARAMETER["False_Easting",28001.642],
PARAMETER["False_Northing",38744.572],
PARAMETER["Central_Meridian",103.8333333333333],
PARAMETER["Scale_Factor",1.0],
PARAMETER["Latitude_Of_Origin",1.366666666666667],
UNIT["Meter",1.0]
]"]`
,如果我用NSLog(@"Location2 : %@", self.mapView.gps.currentPoint.x);
它將返回我一個錯誤不能進入。
'的NSLog(@ 「LOCATION2:%@」,NSStringFromCGPoint(self.mapView.gps.currentPoint));'通過使用它返回我一個錯誤:'傳遞 'AGSPoint *' 不兼容類型的參數'CGPoint'(又名'struct CGPoint');' – sihao 2012-08-14 02:26:09
並感謝它的工作! – sihao 2012-08-14 02:26:47
@ user1495988:對不起,當我意識到你有'AGSMutablePoint'而不是'CGPoint'時,我刪除了額外的建議。我對'currentPoint'返回的內容做了一個糟糕的假設。 – 2012-08-14 02:28:24