轉換MySQL查詢到笨

Question

如何將此查詢轉換爲codeingniter框架：

SELECT sname FROM alumni WHERE email IN (SELECT * FROM alumni_user WHERE uname = '') 

Answer 1

試試這個..

$this->db->select('*'); 

$this->db->from('alumni_user'); 

$this->db->where('uname',''); 

$result = $this->db->get(); 

Answer 2

試試這個：

$q = $this->db->query("SELECT sname FROM alumni WHERE email IN (SELECT * FROM alumni_user WHERE uname = '')"); 

if($q->num_rows() > 0) 
{ 
    $data = $q->result_array(); 
    print_r($data); 
} 
else 
{ 
    echo ''; 
}