PHP表單需要提交兩次

Question

我正在編寫一個應用程序，允許用戶爲潛在員工上傳參考信函。

每個引用都會發送一封電子郵件，其中包含URL末尾的唯一字符串。因此，例如，地址將類似於：www.mywebaddress？url = 503241a20b5085_18720621。

要確定唯一字符串是否有效（即存在於數據庫中），我需要執行查詢搜索。但是，當引用嘗試訪問URL時，他需要回答一個安全問題。因此，我還需要檢查答案是否有效，如果他以前上傳過等，以確定將他重定向到哪個頁面。

但由於查詢，我的代碼要求用戶點擊兩次「提交」。這真的很煩人，但我不知道如何解決它。

這裏是我的代碼相關的摘錄：

if (isset ($_GET['url'])) { 
     $query = "SELECT * FROM ref_info WHERE url='" . $_GET['url'] . "'"; 
     $result = $db->execute($query); 
     if (empty ($result)) { 
      //error message 

     } else { 
      $url = $_GET['url']; 

      if ($_SESSION['validated']) { 
       if ($result[0]['uploaded'] ==1) { 
        $_SESSION['uploaded'] =true; 
       } else { 
        $_SESSION['uploaded'] =false; 
       } 

       include_once("process_upload.php"); 

      } else { 
       if (empty($result[0]['answer'])) { 
        include_once("security.php"); 

       } else { 
        include_once("security_check.php"); 
       } 
      } 
     } 

} 

，請問有什麼我可以做，這樣的形式，只需要提交一次？

在此先感謝您的任何建議！

Answer 1

if (isset ($_GET['url'])) { 
     $query = "SELECT * FROM ref_info WHERE url='" . $_GET['url'] . "'"; //that is really not secure. Take a look at mysql_real_escape_string or something like that in yor $db 
     $result = $db->execute($query); 
     if (empty ($result)) { 
      //error message 

     } else { 
      $url = $_GET['url']; 
      if (empty($result[0]['answer'])) { // page is just opened,form is not yet submitted - ask sequrity question 
       include_once("security.php");  
      } else { //oh. Submit is done - let me check if it is Ok 
       include_once("security_check.php"); 
      } 
      if ($_SESSION['validated']) { //validation is Ok? Yeah. Answer is not posted yet, so validation fails and we do nothing. Just show a form with a question 
       if ($result[0]['uploaded'] ==1) { 
        $_SESSION['uploaded'] =true; 
       } else { 
        $_SESSION['uploaded'] =false; 
       } 

       include_once("process_upload.php"); 

      } 
     } 

}