0
我正在嘗試設置一個腳本,用於抓取YouTube視頻以在PHP中下載它們,這裏是我當前的腳本。從PHP中抓取YouTube上的視頻
<html>
<?php
if(!empty($_POST['name'])) {
$location = htmlspecialchars($_POST['name']);
try {
$handle = fopen($location, "r");
if($handle) {
$contents = '';
while (!feof($handle)) {
$contents .= fread($handle, 8192);
}
fclose($handle);
$result1 = preg_match("/&t=([\w]*)&/",$contents,$tickets);
$result2 = preg_match("/v=(\w*)/",$location,$video_id);
if($result1) {
echo "<a href = \"http://www.youtube.com/get_video?video_id=";
echo $video_id[1];
echo "&t=";
echo $tickets[1];
echo "\">Download link.</a>";
echo "<br>";
echo "Click and Save";
}
else echo "Damn! Click Back and try again..Sorry :(";
}
else echo "\nYou liked that? Ha?";
}
catch(Exception $e) {echo "I made an error. So what? COME AT ME BRO!";}
}
else echo "Empty input! YOU'RE SO STUPID!";
?>
<br><br>
<a href="face.html">Back</a>
</hmtl>
我也有一個簡單的HTML文件,提供的地方YouTube網址粘貼到一個領域,它運行上面的腳本。但是我收到迴音
Damn! Click Back and try again..Sorry :("
我不知道爲什麼我收到此錯誤,代碼看起來固體給我什麼建議?
'的var_dump($內容)'? – jeroen
看看:https://github.com/jeckman/YouTube-Downloader –