我正在使用MS Access在ASP.net(C#)中做一個小應用程序。我有一個Gridview,我有一個「更新」命令。在運行期間,我在RowUpdating()方法中放置了斷點。一切正常,沒有錯誤,參數在後面的代碼中得到更新。但在輸出中,gridview沒有更新,也沒有在數據庫中。Gridview更新錯誤
這裏是代碼:
protected void GridView1_RowUpdating(object sender, GridViewUpdateEventArgs e)
{
string ID = GridView1.Rows[e.RowIndex].Cells[1].Text;
string CName= ((TextBox)GridView1.Rows[e.RowIndex].Cells[2].Controls[0]).Text;
string AName = ((TextBox)GridView1.Rows[e.RowIndex].Cells[3].Controls[0]).Text;
string APhone = ((TextBox)GridView1.Rows[e.RowIndex].Cells[4].Controls[0]).Text;
string AEmail = ((TextBox)GridView1.Rows[e.RowIndex].Cells[5].Controls[0]).Text;
string Note = ((TextBox)GridView1.Rows[e.RowIndex].Cells[6].Controls[0]).Text;
UpdateRecord(ID, CName, AName, APhone, AEmail, Note); // GridView1.EditIndex = -1; BindGridView();
}
UpdateRecord()方法:
更新方法效果很好,使用斷點在運行過程中的所有參數獲取更新的值,但它是未在網格視圖中顯示,未在數據庫中更新
private void UpdateOrAddNewRecord(string ID, string CName, string AName, string APhone, string AEmail, string Note)
{
OleDbConnection connection = null;
string conStr = @"Provider=Microsoft.Jet.OLEDB.4.0;Data Source=C:\Documents and Settings\arjun.giridhar\Desktop\db1.mdb;Persist Security Info=False";
string sqlStatement = "UPDATE Carriers" + " SET CarrierName = @CarrierName, AccountRepName = @AccountRepName, AccountRepContactPhone = @AccountRepContactPhone, AccountRepEmail= @AccountRepEmail, [email protected]" + " WHERE CarrierID = @CarrierID";
try
{
connection = new OleDbConnection(conStr);
connection.Open();
OleDbCommand cmd = new OleDbCommand(sqlStatement, connection);
cmd.Parameters.AddWithValue("@CarrierID", ID);
cmd.Parameters.AddWithValue("@CarrierName", CName);
cmd.Parameters.AddWithValue("@AccountRepName", AName);
cmd.Parameters.AddWithValue("@AccountRepContactPhone", APhone);
cmd.Parameters.AddWithValue("@AccountRepEmail", AEmail);
cmd.Parameters.AddWithValue("@Notes", Note);
cmd.CommandType = CommandType.Text;
cmd.ExecuteNonQuery();
}
catch (Exception ex)
{
string msg = "Update Error:";
msg += ex.Message;
throw new Exception(msg);
}
finally
{
connection.Close();
}
}
BindGridView()方法:
private void BindGridView()
{
DataTable dt = new DataTable();
OleDbConnection connection = new OleDbConnection(conStr);
try
{
connection.Open();
string sqlStatement = "SELECT * FROM Carriers";
OleDbCommand cmd = new OleDbCommand(sqlStatement, connection);
OleDbDataAdapter sqlDa = new OleDbDataAdapter(cmd);
sqlDa.Fill(dt);
if (dt.Rows.Count > 0)
{
GridView1.DataSource = dt;
GridView1.DataSourceID = string.Empty;
GridView1.DataBind();
}
}
catch (System.Data.SqlClient.SqlException ex)
{
string msg = "Fetch Error:";
msg += ex.Message;
throw new Exception(msg);
}
finally
{
connection.Close();
}
}
請給我一個解決方案。
問候, 阿瓊
請附上您的代碼示例 – sharad 2012-02-13 12:59:45
附加代碼將爲您提供更多幫助順便說一句,您有更新後調用Gridview(rebind Gridview)的DataBind()方法。 – Devjosh 2012-02-13 13:02:07
protected void GridView1_RowUpdating(object sender,GridViewUpdateEventArgs e) {string ID = GridView1.Rows [e.RowIndex] .Cells [1] .Text;string CName =((TextBox)GridView1.Rows [e.RowIndex] .Cells [2] .Controls [0])。字符串AName =((TextBox)GridView1.Rows [e.RowIndex] .Cells [3] .Controls [0])。字符串APhone =((TextBox)GridView1.Rows [e.RowIndex] .Cells [4] .Controls [0])。 string AEmail =((TextBox)GridView1.Rows [e.RowIndex] .Cells [5] .Controls [0])。Text; string Note =((TextBox)GridView1.Rows [e.RowIndex] .Cells [6] .Controls [0])。Text; – 2012-02-13 13:13:37