Question

我有不同的參數...在產品上...但我只想顯示那些被用戶點擊的參數。我做了這個，但我想刪除duplicacy ..我的代碼是： -

$ab=$_POST['data1']; 
$karan=explode(",",$ab); 
array_pop($karan); 

for($i=0;$i<count($karan);$i++){ 
    'karan['.$i.'] = '.$karan[$i]; 

    $posts = $wpdb->get_results("SELECT * FROM demo_postmeta WHERE meta_value='".$karan[$i]."' "); 

    $out=array(); 
    foreach($posts as $post){  


     if (!isset($out[$post->post_id])){ 

      $out[$post->post_id][$post->meta_key]=$out; 



      $ram=get_the_post_thumbnail($post->post_id,"_thumbnail_id",true); 
      $title=get_post_meta($post->post_id,"_product_title",true); 
      $price=get_post_meta($post->post_id,"_product_year",true); 
      $link=get_post_meta($post->post_id,"_product_likes",true); 
?>  



<div id="itemListContent" class="in-list"> 
    <div class="the-list"> 
     <div class="li first row clearfix" style="cursor: pointer;"> 
      <div class="c-1 table-cell"> 
       <div class="cropit"> 
        <a class="pics-lnk important-rule" href="http://uzodocs.com/PROJECTS/demo/products?post_id=<?php echo $post->post_id ?>" style="text-decoration: none;"> 
         <?php echo $ram; ?> 
        </a> 
       </div> 
      </div> 
      <div class="second-column-container table-cell"> 
       <h3> 
        <a href="http://uzodocs.com/PROJECTS/demo/products?post_id=<?php echo $post->post_id ?>" title="Kenxinda Watch Mobile Dual SIM with FREE Bluetooth Headset free home delivery - Delhi" class="important-rule" style="text-decoration: none;"> 
         <?php echo $title; ?> 
        </a> 
       </h3> 
       <div class="c-4"> 
       </div> 
       <span class="itemlistinginfo clearfix"> 
        <span> 
         Delhi | 
         Cameras 
         - Camera Accessories 
        </span> 
        <span> 
        </span> 
       </span> 
      </div> 
      <div class="third-column-container table-cell"> 

       <?php echo $price; ?> 

      </div> 

      <div class="fourth-column-container table-cell"><br> </div> 
     </div> 
     <div class="li even row clearfix" style="cursor: pointer;"> 
      <div class="c-1 table-cell"> 
      </div> 

     </div> 
    </div> 
</div> 

<?php  

     } 
     $out[$post->post_id][$post->meta_key][] = $post->post_id; 


    } 


} 
die; 

?> 

Answer 1

UPDATE： 這可能是解決你的問題的方式：

if (!in_array($post->post_id, $out)){ 

     $out[] = $post->post_id; 

您可以刪除最後$out[$post->post_id][$post->meta_key][] = $post->post_id;

Answer 2

只需將您所需的數據輸入到 $ out [$ post-> post_id] [$ post-> meta_key] [] =「您需要的數據」。 並將該數組放在範圍外。死前;