使用xslt從xml中刪除重複項

如何使用xslt從下面的xml中刪除重複項。以下是我正在使用的代碼。它工作正常的刪除重複項，但我無法添加相應的值使用xslt從xml中刪除重複項

<schedules> 
     <flight> 
     <Flight> 
     <fno>122</fno> 
     <acode>aa</acode> 
     <Dest1IATA>ATL</Dest1IATA> 
     <Dest1desc>Atlanta Airport</Dest1desc> 
     <Dest1town>Atlanta </Dest1town> 
     <Dest2IATA>JFK</Dest2IATA>   
     <Dest2desc></Dest2desc> 
     <Dest2town></Dest2town> 
     <Dest2cntry></Dest2cntry>    
     <Dest3IATA>LGA</Dest3IATA>   
     <Dest3desc></Dest3desc> 
     <Dest3town></Dest3town> 
     <Dest3cntry></Dest3cntry> 
     </Flight> 
      <Flight> 
     <fno>124</fno> 
     <acode>aB</acode> 
     <Dest1IATA>LCY</Dest1IATA> 
     <Dest1desc>LCY Airport</Dest1desc> 
     <Dest1town>LCY</Dest1town> 
     <Dest2IATA>DXB</Dest2IATA>   
     <Dest2desc></Dest2desc> 
     <Dest2town></Dest2town> 
     <Dest2cntry></Dest2cntry>    
     <Dest3IATA>LGA</Dest3IATA>   
     <Dest3desc></Dest3desc> 
     <Dest3town></Dest3town> 
     <Dest3cntry></Dest3cntry> 
     </Flight>   
     </flight> 
     </schedules>

XSLT代碼：

 <xsl:for-each select="(//schedules/flight/Flight/Dest1IATA | //schedules/flight/Flight/Dest2IATA | //schedules/flight/Flight/Dest3IATA)[generate-id(.) = generate-id(key('Keycity', .))]"> 
     <xsl:sort select="//schedules/flight/Flight/Dest1IATA | //schedules/flight/Flight/Dest2IATA | //schedules/flight/Flight/Dest3IATA"/> 

     <!--<xsl:value-of select="." />--> 
     <xsl:if test="local-name() = 'Dest1IATA' and //schedules/flight/Flight/Dest1IATA != ''"> 
     <Row Action="ADD"> 
      <xsl:value-of select="." />|<xsl:value-of select="//schedules/flight/Flight/Dest1desc" />|<xsl:value-of select="//schedules/flight/Flight/Dest1town" />|<xsl:value-of select="//schedules/flight/Flight/Dest1cntry" /> 
     </Row> 
     </xsl:if> 
     <xsl:if test="local-name() = 'Dest2IATA' and //schedules/flight/Flight/Dest2IATA != ''"> 
     <Row Action="ADD"> 
      <xsl:value-of select="." />|<xsl:value-of select="//schedules/flight/Flight/Dest2desc" />|<xsl:value-of select="//schedules/flight/Flight/Dest2town" />|<xsl:value-of select="//schedules/flight/Flight/Dest2cntry" /> 
     </Row> 
     </xsl:if> 
     <xsl:if test="local-name() = 'Dest3IATA' and //schedules/flight/Flight/Dest3IATA != ''"> 
     <Row Action="ADD"> 
      <xsl:value-of select="." />|<xsl:value-of select="//schedules/flight/Flight/Dest3desc" />|<xsl:value-of select="//schedules/flight/Flight/Dest3town" />|<xsl:value-of select="//schedules/flight/Flight/Dest3cntry" /> 
     </Row> 
     </xsl:if> 
    </xsl:for-each>

ExpectedOutput應該

ROW|Add|ATL|Atlanta Airport| 
ROW|Add|JFK|| 
ROW|Add|LGA|| 
ROW|Add|LCY|LCYAirport|LCY 
ROW|Add|DXB||

輸出與上面的代碼

ROW|Add|ATL|| 
ROW|Add|JFK|| 
ROW|Add|LGA|| 
ROW|Add|LCY|| 
ROW|Add|DXB||

來源

2016-07-14 user3067170

你需要解釋什麼是「相應的值」。 - P.S.當我建議你應該關閉[你以前的問題]（http://stackoverflow.com/questions/38362143/how-to-remove-duplicates-when-using-xslt），我不是說你應該刪除它。 –

抱歉，我沒有看到關閉它的選項。相應的值是該目的地的國家/地區，城鎮和描述 – user3067170

您通過接受答案來結束問題。 –

The以下樣式表產生的輸出與您所期望的非常相似。這可能是一個幸運的猜測，或者只是一個巧合。

XSLT 1.0

<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> 
<xsl:output method="text" encoding="UTF-8"/> 

<xsl:key name="dest" match="Dest1IATA | Dest2IATA | Dest3IATA" use="." /> 

<xsl:template match="/schedules"> 
    <xsl:for-each select="(flight/Flight/Dest1IATA | flight/Flight/Dest2IATA | flight/Flight/Dest3IATA)[generate-id(.) = generate-id(key('dest', .))]"> 
     <xsl:text>ROW|Add|</xsl:text> 
     <xsl:value-of select="." /> 
     <xsl:if test="self::Dest1IATA"> 
      <xsl:text>|</xsl:text> 
      <xsl:value-of select="../Dest1desc" /> 
      <xsl:text>|</xsl:text> 
      <xsl:value-of select="../Dest1town" />  
     </xsl:if> 
     <xsl:text>&#10;</xsl:text> 
    </xsl:for-each> 
</xsl:template> 

</xsl:stylesheet>

應用到你的輸入例子，結果將是：

ROW|Add|ATL|Atlanta Airport|Atlanta 
ROW|Add|JFK 
ROW|Add|LGA 
ROW|Add|LCY|LCY Airport|LCY 
ROW|Add|DXB

來源

2016-07-14 16:55:01

使用xslt從xml中刪除重複項

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