按鈕響應UIControlEventTouchUpInside並觸及方法

我創建了一個按鈕：按鈕響應UIControlEventTouchUpInside並觸及方法

button = [StretchableButton new]; 
[button addTarget:mainViewController action:@selector(addNumberFromButton:) forControlEvents:UIControlEventTouchUpInside];

裏面的StretchableButton I類有：

- (void)touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event { 
    [self.nextResponder touchesBegan:touches withEvent:event]; 
} 

- (void)touchesMoved:(NSSet *)touches withEvent:(UIEvent *)event { 
    [self.nextResponder touchesMoved:touches withEvent:event]; 
} 

- (void)touchesEnded:(NSSet *)touches withEvent:(UIEvent *)event { 
    [self.nextResponder touchesEnded:touches withEvent:event]; 
}

觸摸方法被調用，但button沒有的點擊反應。

任何人都可以幫助我嗎？

來源

2012-02-29 Radislav

我不知道你正在試圖讓按鈕在這裏做...你是不是想使拖動的按鈕的寬度擴大？（我猜是因爲你稱之爲可拉伸按鈕） – mdominick 2012-02-29 14:17:13

對不起，我的英文。我有按鈕查看。如果觸摸按鈕並將其拉出，我想用手指移動視圖。如果我只是觸摸按鈕，我想調用方法addNumberFromButton： – Radislav 2012-02-29 14:19:34

好的。由sch列出的超級事物應該工作。祝你好運。 – mdominick 2012-02-29 14:24:11

添加手勢識別，代碼示例：

UIPanGestureRecognizer *gesturePan = [[UIPanGestureRecognizer alloc] initWithTarget:self action:@selector(pan:)]; 
    gesturePan.maximumNumberOfTouches = 1; 
    gesturePan.minimumNumberOfTouches = 1; 
    gesturePan.delegate = self; 
    [myButton addGestureRecognizer:gesturePan]; 
    [gesturePan release];

....

- (void)pan:(UIPanGestureRecognizer *)gesture 
{ 
    if ((gesture.state == UIGestureRecognizerStateChanged) || 
     (gesture.state == UIGestureRecognizerStateEnded)) { 


    CGPoint location = [gesture locationInView:[gesture.view superView]]; 
//add calculation view location on it superview 
    [gesture.view superView] setCenter:newLocation]; 

}

來源

2012-02-29 14:28:41 NeverBe

按鈕響應UIControlEventTouchUpInside並觸及方法

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