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我定義了一個複合材料部件(實際數),當我嘗試重新呈現插入組件我的錯誤中提到:錯誤:<f:ajax>包含未知的ID複合使用時:insertChildren
<f:ajax> contains an unknown id ':contentFrm' - cannot locate it in the context of the component j_idt40
如果我只需更換:
<et:pageContent formId="contentFrm">
與
<h:form id="contentFrm">
<div>
使用相同的組件
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml"
xmlns:h="http://java.sun.com/jsf/html"
xmlns:composite="http://java.sun.com/jsf/composite">
<composite:interface>
<composite:attribute name="styleClass" default="access-box-content alpha omega grid-12" />
<composite:attribute name="formId" default="#{cc.attrs.id}" />
</composite:interface>
<composite:implementation>
<h:form id="#{cc.attrs.formId}">
<div class="#{cc.attrs.styleClass}">
<composite:insertChildren/>
</div>
</h:form>
</composite:implementation>
</html>
這是我如何使用複合
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<ui:composition id="landing" xmlns="http://www.w3.org/1999/xhtml"
xmlns:f="http://java.sun.com/jsf/core"
xmlns:h="http://java.sun.com/jsf/html"
xmlns:ui="http://java.sun.com/jsf/facelets"
xmlns:et="http://java.sun.com/jsf/composite/components"
template="/layout/template.xhtml"
xmlns:c="http://java.sun.com/jsp/jstl/core">
<ui:define name="main-content">
<et:pageTitle title="#{msg.trx_lastTrx}" />
<et:tabBar formId="currentTrxFrm">
<et:tab bean="#{accountTransactionBacking}"
prompt="#{msg.trx_currentTrxs}"
reRender=":contentFrm"
tabId="1"
active="true"/>
</et:tabBar>
<et:pageContent formId="contentFrm">
<et:tabContentPanel rendered="#{accountTransactionBacking.selectedTab ==1}">
<ui:include src="/app/summary/currentTrxRG.xhtml" rendered="#{accountTransactionBacking.selectedTab ==1}"/>
</et:tabContentPanel>
</et:pageContent>
</ui:define>
</ui:composition>
TIA
一些測試..:
然後一切工作正常
下面是相關代碼得到相同的結果..例如下面的代碼給出了類似的錯誤(甚至用render =「accountSummaryLines」替換render =「accountSummaryLines」)。 。
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<ui:composition id="landing" xmlns="http://www.w3.org/1999/xhtml"
xmlns:f="http://java.sun.com/jsf/core"
xmlns:h="http://java.sun.com/jsf/html"
xmlns:ui="http://java.sun.com/jsf/facelets"
xmlns:et="http://java.sun.com/jsf/composite/components"
template="/layout/template.xhtml"
xmlns:c="http://java.sun.com/jsp/jstl/core">
<ui:define name="main-content">
<et:pageTitle title="#{msg.ls_lastStatement}" />
<et:tabBar formId="acctSummTabFrm">
<et:tab/>
</et:tabBar>
<et:pageContent formId="accountButtonsFrm">
....
<et:div styleClass="accountSummaryLines" divId="lastStatementLines">
<ui:repeat var="row" value="#{lastStatementBacking.lines.data}">
<h:outputText escape="false" value="#{row}" styleClass="grid-12 lastStatementDetail"/><br></br>
</ui:repeat>
</et:div>
<et:div styleClass="access-box-footer">
<h:commandButton styleClass="left" action="#{lastStatementBacking.lines.prevPage}" value="#{msg.buttonPrevPage}" style="float:left;">
<f:ajax render="accountSummaryLines" />
</h:commandButton>
<h:commandButton styleClass="right" action="#{lastStatementBacking.lines.nextPage}" value="#{msg.buttonNextPage}">
<f:ajax render="accountSummaryLines" />
</h:commandButton>
</et:div>
</et:pageContent>
</ui:define>
</ui:composition>
我得到這個特別的例子是使用渲染=「@形式」的工作,像這樣的唯一途徑..
Thanks @BalusC!這解決了我的問題..我實際上離開了'