如何插入相同的UUID在兩個不同的表

Question

的兩排我嘗試下一個腳本：

// Insert data into mysql 

$qry="INSERT INTO $tbl_name1 (ID, REFERENCE, CODE, NAME) VALUES (UUID(), '$REFERENCE', '$CODE', '$NAME')"; 
$result=mysql_query($qry); 

$qry2="INSERT INTO $tbl_name2 (PRODUCT) VALUES ('$ID')"; <--- Here is a problem 
$result=mysql_query($qry2) 

我不知道該怎麼兩個插入相同的UUID在simultanoiusly兩個表。請幫幫我！ 我將非常感謝您的支持！

DONE !!! 的工作腳本：

$q = "SELECT UUID() AS uid"; 
$res = mysql_query($q) or die('q error: '.mysql_error()); 
$row = mysql_fetch_assoc($res); 

// Insert data into mysql 
$qry="INSERT INTO $tbl_name1 (ID, REFERENCE, CODE, NAME) VALUES ('".$row['uid']."', '$REFERENCE', '$CODE', '$NAME')"; 
$result=mysql_query($qry) or die('err 034r '.mysql_error()); 

$qry2="INSERT INTO $tbl_name2 (PRODUCT) VALUES ('".$row['uid']."')"; 
$result=mysql_query($qry2) or die('gg2345 '.mysql_error()); 

Answer 1

只是做SELECT UUID()和這些值放到語句中的PHP。像這樣（未經）：

$result = mysql_query("SELECT UUID() AS UUID") or die('SQL error: ' . mysql_error()); 
$row = mysql_fetch_assoc($result); 
$UUID = $row["UUID"]; 

$qry="INSERT INTO $tbl_name1 (ID, REFERENCE, CODE, NAME) VALUES ('$UUID', '$REFERENCE', '$CODE', '$NAME')"; 
$result=mysql_query($qry); 

$qry2="INSERT INTO $tbl_name2 (PRODUCT) VALUES ('$UUID ')"; <--- Here is a problem 
$result=mysql_query($qry2) 

另一種方法是使用用戶定義的變量（see SQL Fiddle）：

SET @UUID = (SELECT UUID() AS UUID); 
INSERT INTO test1 VALUES(@UUID, "foo"); 
INSERT INTO test1 VALUES(@UUID, "bar"); 

Answer 2

假設ID是表唯一索引之前還是可以$qry2補充：您發送INSERT年代以前

$ID = mysql_insert_id();