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我想在給定的點上繪製曲面。我想獲得任意點的z座標。我不明白爲什麼scipy.interpolate.griddata和scipy.interpolate.RectBivariateSpline爲相同的x和y座標返回不同的值。我哪裏做錯了?爲什麼scipy.interpolate.griddata和scipy.interpolate.RectBivariateSpline返回不同的值?
import numpy as np
from scipy.interpolate import griddata, RectBivariateSpline
from mpl_toolkits.mplot3d import Axes3D
import matplotlib.pyplot as plt
x_list = np.array([ 10.0, 10.0, 0.0, 0.0])
y_list = np.array([ 0.0, 10.0, 10.0, 0.0])
z_list = np.array([103.95, 105.5, 104.85, 104.6])
xi = np.linspace(min(x_list), max(x_list),11)
yi = np.linspace(min(y_list), max(y_list),11)
grid_x, grid_y = np.meshgrid(xi, yi)
grid_z1 = griddata((x_list, y_list), z_list, (grid_x, grid_y), method='nearest')
grid_z2 = griddata((x_list, y_list), z_list, (grid_x, grid_y), method='linear')
grid_z3 = griddata((x_list, y_list), z_list, (grid_x, grid_y), method='cubic')
z = RectBivariateSpline(xi, yi, grid_z2, kx=1, ky=1, s=0)
print z(10.0, 0.0)[0,0] #return 104.85!!! Must be 103.95.
fig = plt.figure()
ax1 = fig.add_subplot(221, projection='3d')
surf = ax1.plot_surface(grid_x, grid_y, grid_z1)
ax1.set_xlabel(u'X')
ax1.set_ylabel(u'Y')
ax1.set_zlabel(u'Z')
ax2 = fig.add_subplot(222, projection='3d')
surf = ax2.plot_surface(grid_x, grid_y, grid_z2)
ax2.set_xlabel(u'X')
ax2.set_ylabel(u'Y')
ax2.set_zlabel(u'Z')
ax3 = fig.add_subplot(223, projection='3d')
surf = ax3.plot_surface(grid_x, grid_y, grid_z3)
ax3.set_xlabel(u'X')
ax3.set_ylabel(u'Y')
ax3.set_zlabel(u'Z')
plt.show()
它們不就是不同的插值方法嗎?你不能指望這些值完全相同。 – BrenBarn 2014-11-14 22:34:16
我不確定你想要用你的代碼做什麼,但是你可能會陷入'np.meshgrid'的Matlabesque行爲。看到這個討論[這裏](https://github.com/scipy/scipy/issues/3164)。 TLDR:改變meshgrid的輸入順序,然後再試一次 – cd98 2014-11-14 22:59:15
是的,只需要改變:'grid_y,grid_x = np.meshgrid(xi,yi)',我認爲現在應該起作用。 (如果您確認這是問題,請解釋回答中發生了什麼,以便回到此問題的人確切知道發生了什麼) – cd98 2014-11-14 23:02:49