一些奇怪的東西正在發生的事情:if-else語句未定義的對象
JSON:
{
"all": {
"id": [
"64",
"65"
],
"code": [
"AqCeTZ3Q",
"CTRtldIw"
],
"file_match": [
"voorbeeld.php",
"Handeler.rar"
],
"file_size": [
"30",
"146693"
],
"expire": [
"1386543600",
"1386543600"
],
"ip": [
"dada",
""
],
"can_used": [
"0",
"1"
],
"opmerking": [
"",
""
]
},
"id": [
"65"
],
"active": {
"code": [
"CTRtldIw"
],
"file_match": [
"Handeler.rar"
],
"file_size": [
"146693"
],
"expire": [
"1386543600"
],
"ip": [
""
],
"can_used": [
"1"
],
"opmerking": [
""
]
},
"expired": {
"id": [
"64"
],
"code": [
"AqCeTZ3Q"
],
"file_match": [
"voorbeeld.php"
],
"file_size": [
"30"
],
"expire": [
"1386543600"
],
"ip": [
"dada"
],
"can_used": [
"0"
],
"opmerking": [
""
]
}
}
腳本1(作品):
function update() {
var value = document.getElementById("chooser").value;
$.ajax({
url: "./json.php",
dataType: 'json',
success: function(data, value) {
alert(data.all.id);
}
});
}
輸出:一個值警報:64, 65。正確!
腳本2:(沒有工作,我不知道爲什麼。)
function update() {
var value = document.getElementById("chooser").value;
$.ajax({
url: "./json.php",
dataType: 'json',
success: function(data, value) {
if(value == all) {
alert(data.all.id);
} else if (value == active) {
alert(data.active.id);
} else { // expired
alert(data.expired.id);
}
}
});
}
錯誤:未捕獲的ReferenceError:一切都沒有確定。 (當值==所有)
所以,我不知道爲什麼腳本被打破,當我添加一個語句。有人知道爲什麼這不起作用,以及如何解決它?
需要使用瀏覽器控制檯來查看拋出的錯誤....'all''和'active'未定義,這些錯誤將顯示在控制檯中 – charlietfl