0
我的代碼被設計爲在listview中有一個單一項目的兩個複選框,問題是當我點擊第一個複選框時,另一個複選框被自動點擊,我取消選中其中一個,另一個自動取消選中單個項目調用位置的兩個複選框
我認爲問題在於兩個複選框獲取該項目的位置,因此它們具有相同的位置,我需要每個複選框都有它自己的複選框位置
@Override public View getView(final int position, View convertView, ViewGroup parent) {
ViewHolder holder=null;
View itemView = convertView;
if (itemView == null){
LayoutInflater inflater = (LayoutInflater) ctx.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
itemView = inflater.inflate(R.layout.item, null);
holder = new ViewHolder();
holder.textView1 = (TextView) itemView.findViewById(R.id.textView1);
holder.check1 = (CheckBox) itemView.findViewById(R.id.check1);
holder.check2 = (CheckBox) itemView.findViewById(R.id.check2);
itemView.setTag(holder);
}
else{
holder = (ViewHolder) itemView.getTag();
}
holder.check1.setTag(position);
final Item item = items.get(position);
holder.textView1.setText(item.getName());
holder.check1.setOnCheckedChangeListener(new CompoundButton.OnCheckedChangeListener() {
@Override
public void onCheckedChanged(CompoundButton buttonView,boolean isChecked) {
if(buttonView.isPressed()){
if (position != ListView.INVALID_POSITION) {
Item p = items.get(position);
p.setSelected(isChecked);
}
}
}
}
);
holder.check2.setOnCheckedChangeListener(new CompoundButton.OnCheckedChangeListener() {
@Override
public void onCheckedChanged(CompoundButton buttonView,boolean isChecked) {
if(buttonView.isPressed()){
if (position != ListView.INVALID_POSITION) {
Item p = items.get(position);
p.setSelected(isChecked);
}
}
}
}
);
holder.check1.setChecked(item.isSelected());
holder.check2.setChecked(item.isSelected());
return itemView;
}
}private static class ViewHolder {
public TextView textView1;
public CheckBox check2,check1;
}}
太感謝你了,它的工作原理 –