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我想在zend框架2中編寫如下的mySQL查詢:如何在zend2中編寫複雜的sql查詢
如何將它轉換爲zend db選擇約定?
SELECT profiles.*,
user.email,
user.first_name,
user.last_name,
portfilio_images.profileImage,
images.url AS imgurl
FROM profiles
INNER JOIN user ON user.user_id = profiles.ownerId
LEFT JOIN (
SELECT *
FROM portfilio_images
WHERE portfilio_images.profileImage = '1'
) as portfilio_images ON portfilio_images.profileId = profiles.id
LEFT JOIN images ON images.id = portfilio_images.imageId
WHERE profiles.ownerId != '4' AND (profiles.name LIKE '%a%' OR user.first_name LIKE '%a%' OR user.last_name LIKE '%a%')
GROUP BY user.user_id
我有一個寫了關於加入,或許它會幫助你: http://stackoverflow.com/questions/14354802/tablegateway-with-multiple-from-表/ 14371056#14371056 – Diemuzi 2013-03-07 14:18:45
謝謝你鏈接Diemuzi,其實在這個查詢中,我遇到了兩個困難。第一個是它有一個帶有條件的innser select查詢,第二個放置在帶括號的條件下。對我來說這很複雜,因爲我找不到用圓括號設置條件,所以我臨時爲「$ where [] =」(profiles.name LIKE'%「。$ search。」%'或user.first_name LIKE '%'。$ search。「%'或user.last_name LIKE'%」。$ search。「%')」;「但這絕對是我不喜歡的。 – 2013-03-13 05:31:54