Javascript - 通話功能2內功能1，然後繼續

Question

可能嗎？這個怎麼做？點擊按鈕時，我打電話給function1。如果條件爲真（i==1），則function1會暫停，並且僅在function2完全執行後纔會執行以下代碼。例如：

function1(i){ 
    //some code here 
    if(i == 1){ 
     function2(i); // call function2 and waits the return to continue 
    } 
    //the following code 
} 

function2(i){ 
    //do something here and returns 
} 

Answer 1

在這裏你去：

function1(i){ 
    //some code here 
    if(i == 1){ 
     function2(i); // call function2 and waits the return to continue 
    } 
    //the following code 
} 

function2(i){ 
    //do something here and returns 
} 

如果你意味着function2實際上是異步以某種方式：

function1(i){ 
    //some code here 
    if(i == 1){ 
     // call function2 and waits for return to continue 
     function2(i, function() { 
      // the following code 
     }); 
    } 
    else { 
     //the following code 
    } 
} 

function2(i, callback){ 
    //do something async here and return when complete 
    setTimeout(callback, 1000); 
}