這是我的PHP代碼php if elseif然後呢?
我已經在代碼部分的註釋中提到的問題點
if(isset($_POST['submit']))
{
if(isset($_POST['rdoption1']))
{
$var1 = $_POST["rdoption1"];
}
if(isset($_POST['rdoption2']))
{
$var2 = $_POST["rdoption2"];
}
if(!isset($_POST['rdoption1']))
{
$message = "Please select Option1";
}
elseif(!isset($_POST['rdoption2']))
{
$message = "Please select Option2";
}
elseif($_POST['rdoption2'] == "checkSetXY")
{
if($_POST["valXLocation"] == "")
{
$message = "You forget to enter X value.";
}
elseif($_POST["valYLocation"] == "")
{
$message = "You forget to enter Y value.";
}
} // till here all is good. I get all error messages if anything is left vacant or not clicked on radio button
elseif(empty($_POST['txtoption3'])) //this is not working //the issue is if i select rdoption1 any option and rdoption2 checkDefault next code logic work.. but next code logic does not work when i click on the radio of checkSetXY and enter x and y values.. It simply does not execute code further..
{
$message = "Please enter your name.";
}
else
{
//insert into db
}
}
這是HTML表單與PHP的回聲 這裏我得到的消息,他們應是但不當我選擇checkSetXY
值
<?php if(!empty($message)){ echo $message; } ?>
<form id="form1" name="form1" method="post" action="form1.php">
Space portion:
<input type="radio" name="rdoption1" value="RJ"/>space 1
<input type="radio" name="rdoption1" value="SM" />space 2
Pixel Location
<div class="formText">
<input type="radio" name="rdoption2" value="checkSetXY"/> Specify Location
X: <input type="text" id="locField" name="valXLocation">
Y: <input type="text" id="locField" name="valYLocation">
<input type="radio" name="rdoption2" value="checkDefault"/>Default
<input type="text" class="input" name="txtoption3">
<input type="submit" name="submit" value="Submit">
</form>
現在我很困惑爲什麼不採取elseif
的txtoption3
任何幫助?在此先感謝
試着在這個IF/IF ELSE/ELSE序列上做一個圖表,因爲它可能有點頭暈! – fedorqui 2013-02-09 12:50:23
問題是如果我選擇rdoption1任何選項和rdoption2 checkDefault下一個代碼邏輯工作..但下一個代碼邏輯不起作用,當我點擊CheckSetXY的無線電並輸入x和y值..它只是不會進一步執行代碼。 。 – ashis 2013-02-09 13:01:42