Rails路由返回url

Question

我已經爲kannel這種方式設置了短信應用程序的delivery報告的投遞網址;

id = rand(36**8).to_s(36) 
https://www.xxxxxxxx.com/messages/delivery?id=#{id}&type=%d 

，並在消息控制器

def delivery 
sent_message = SentMessage.find_by_ref(params[:id]) 
if params[:type] == 1 
    sent_message.delivery = "Delivered" 
    sent_message.save() 
elsif params[:type] == 2 
    sent_message.delivery = "Delivery Failure" 
    sent_message.save() 
else 
    sent_message.save() 
end 

從我的路線文件是下面是該行

match 'message/:id/delivery' => 'messages#delivery', :as => :deliver 

有人幫我指出錯誤，因爲送達報告根本就沒有被報道。

非常感謝您

Answer 1

對於喜歡https://www.xxxxxxxx.com/messages/delivery?id=#{id}&type=%d路線，你應該使用：

match 'messages/delivery' => 'messages#delivery', :as => :deliver