印刷元素

Question

if select == '2': 
    print('Displaying all employees\n') 
    print('Employee names:\n') 
    for records in record: 
     print(record[0]) 

我的第一次選擇工作完全正常，但是 我的第二optiond不會從名單打印出來的「enterName」。我該如何解決？我試圖找到答案，但我找不到足夠具體的答案。

感謝您的期待，並幫助我:)。

此外，我的另一個問題是，當試圖添加多個「新員工」它會覆蓋第一個，我該如何解決這個問題？

Answer 1

有兩個問題。首先是打印員工。你在做什麼是打印整個陣列而不是for循環的項目。

第二個問題是，每次選擇「1」時都會重新創建record。你可能應該把它放在while循環之前。

我也修正了身份。我希望現在好一點。

例如：

select=True 
record=[] 
while select: 
    print (""" 
Personnel Database 
    1. Add a new employee 
    2. Display all employees 
    3. Search for an employee 
    4. View full-time employees 
    5. View part-time employees 
    6. View number of employee records in database 
    7. Delete an employee from the database 
    8. Exit 
    Choose an option (1-7) or 8 to Exit 
    """) 
    select=input("What would you like to do? ") 
    if select == "1": 
     print("Add a new employee") 
     enterName = input ("Enter employee name:") 
     enterTitle = input ("Enter employee Job title:") 
     enterRate = float (input ("Enter employee hourly rate:£")) 
     enterService = float(input ("Enter number of years service:")) 
     fulltime = input ("Is the employee full-time? Y/N:") 
     if fulltime.capitalize == "Y": 
      break 
     elif fulltime == "N": 
      break 

     record.append((enterName, enterTitle, enterRate, enterService, fulltime)) 
     print ("The employee you have entered is:",record) 

    if select == "2": 
     print ("Displaying all employees") 
     print ("Employee names:") 
     for r in record: 
      print(r[0])