無效，因爲「或」在Python

straightrunfaces = 'A23456789TJQKA'; 
for i in range(0,10): 
     if ((counts[straightrunfaces[i]] and 
      counts[straightrunfaces[i+1]] and 
      counts[straightrunfaces[i+2]] and 
      counts[straightrunfaces[i+3]])) or 
      ((counts[straightrunfaces[i+1]] and 
      counts[straightrunfaces[i+2]] and 
      counts[straightrunfaces[i+3]] and 
      counts[straightrunfaces[i+4]])): 



C:\datasci_course_materials\assignment3>python poker.py 
    File "poker.py", line 62 
    counts[straightrunfaces[i+3]])) or 
            ^
**SyntaxError: invalid syntax**

操作語法，我不明白爲什麼「或」經營者不工作無效，因爲「或」在Python

來源

2013-05-28 vkaul11

你爲什麼有雙重'（（..））' - 擺脫它之一。 – karthikr

的問題是不是or，它是在最後的換行符。再也沒有開放的括號，所以換行符終止了if聲明;但是，if語句必須以冒號結尾，而您的語句不會與解析器結尾。括號

if (counts[straightrunfaces[i]] and 
    counts[straightrunfaces[i+1]] and 
    counts[straightrunfaces[i+2]] and 
    counts[straightrunfaces[i+3]]) or \ 
    (counts[straightrunfaces[i+1]] and 
    counts[straightrunfaces[i+2]] and 
    counts[straightrunfaces[i+3]] and 
    counts[straightrunfaces[i+4]]):

或包裹了整個事情：

要麼添加一個明確的續行

if ((counts[straightrunfaces[i]] and 
    counts[straightrunfaces[i+1]] and 
    counts[straightrunfaces[i+2]] and 
    counts[straightrunfaces[i+3]]) or 
    (counts[straightrunfaces[i+1]] and 
    counts[straightrunfaces[i+2]] and 
    counts[straightrunfaces[i+3]] and 
    counts[straightrunfaces[i+4]])):

PEP 8建議後者。

來源

2013-05-28 03:13:00 Cairnarvon

非常感謝您的提示 – vkaul11

嘗試：

straightrunfaces = 'A23456789TJQKA'; 
for i in range(0,10): 
    if all(counts[straightrunfaces[i]], counts[straightrunfaces[i+1]], counts[straightrunfaces[i+2]], counts[straightrunfaces[i+3]]) or all(counts[straightrunfaces[i+1]], counts[straightrunfaces[i+2]], counts[straightrunfaces[i+3]], counts[straightrunfaces[i+4]]):

來源

2013-05-28 03:13:22 karthikr

無效，因爲「或」在Python

回答

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