軌HAML語法錯誤，意想不到的keyword_ensure，期待$結束

Question

我得到在我的崗位語法錯誤局部視圖

.row-fluid{ :style => "margin:auto;"} 
%span{:style => "display:inline-block"} 
    .row 
     %h5{:style => "display:inline-block"}= link_to user.username, user_posts_path(user) 
     -if post.from_id 
      %i.icon-small.icon-refresh{:style => "display:inline-block"} 
      %h5{:style => "display:inline-block"}=link_to User.find(post.from_id).username, user_posts_path(User.find(post.from_id)) 
     -if post.source_id && post.source_id != post.user_id 
      %h5.offset4{:style => "display:inline-block"} Source: 
      %h5{:style => "display:inline-block"}= link_to User.find(post.source_id).username, user_posts_path(User.find(post.source_id)) 
     -if authenticateOwnership(user.id) 
      =link_to "", user_post_path(user,post) 
       %i.icon.icon-trash 
    %li.thumbnail 
     %a.thumbnail 
      %img{ :src => "/uploads/#{@user.username}/#{post.id}/image",:style => "display:block; max-width:600px"} 
     .caption 
      %blockquote{:style => "margin:10 10 10 20"} 
      %p= " " + post.content 

一些挖後，麻煩的線條顯得

-if authenticateOwnership(user.id) 
    =link_to "", user_post_path(user,post) 
     %i.icon.icon-trash 

這裏我的authenticateOwnership方法（應用程序控制器）

def authenticateOwnership(userid) 
    if currentuser.id != userid 
    return false 
    end 
return true 
end 

如果我刪除link_to標記它的工作S作爲預期沒有錯誤

Answer 1

你肯定意味着：

- if authenticateOwnership(user.id) 
    = link_to user_post_path(user,post) do 
    %i.icon.icon-trash