2015-11-12 56 views
0

我試圖從輸入框中的URL獲取圖像。實質上,我想將圖像URL轉換爲文件對象。JavaScript:將圖像URL轉換爲文件對象

爲了便於比較,如果您訪問Google圖片並選擇一張隨機圖片,則可以複製圖片或圖片的網址。

在我的情況下,用戶會抓住該URL(如https://pbs.twimg.com/profile_images/638751551457103872/KN-NzuRl.png)並粘貼到輸入框中,然後單擊我的「添加圖像」按鈕。我想本地訪問這個圖像文件的URL,我可以傳遞到ng-file-upload的一個函數Upload.dataUrl(myImageFile),它將爲我做上傳。

目前,我已經檢查過,以確保它的網址是一個有效的圖像,但我不知道如何得到圖像(圖像的URL與圖像)。

formSubmit: function(){ 
     var url = document.forms["imageForm"].elements["urlImage"].value; 
     console.log(url); 
     if (!$scope.checkURL(url)) { 
     console.log("It looks like the url that you had provided is not valid! Please only submit correct image file. We only support these extensions:- jpeg, jpg, gif, png.") 
     return(false); 
     } 
     $scope.testImage(url, function(testURL, result) { 
     if (result == "success") { 
      // you can submit the form now 
      console.log("SUCCESS!"); 
      //document.forms["submitForm"].submit(); 

      //!!!---------------------!!! 
      //Correct URL link, but not sure how to get the image from URL 
      //!!!---------------------!!! 

     } 
     else if (result == "error") { 
      console.log("The image URL does not point to an image or the correct type of image."); 
     } 
     else { 
      console.log("The image URL was not reachable. Check that the URL is correct."); 
     } 
     }); 
     return(false); // can't submit the form yet, it will get sumbitted in the callback 

    }, 
    checkURL: function(url){ 
     return(url.match(/\.(jpeg|jpg|gif|png)$/) != null); 
    }, 
    testImage: function(url, callback, timeout) { 
     timeout = timeout || 5000; 
     var timedOut = false, timer; 
     var img = new Image(); 
     img.onerror = img.onabort = function() { 
      if (!timedOut) { 
       clearTimeout(timer); 
       callback(url, "error"); 
      } 
     }; 
     img.onload = function() { 
      if (!timedOut) { 
       clearTimeout(timer); 
       callback(url, "success"); 
      } 
     }; 
     img.src = url; 
     timer = setTimeout(function() { 
      timedOut = true; 
      callback(url, "timeout"); 
     }, timeout); 
    } 

任何援助將不勝感激!

+1

什麼* *正是你說的意思*「獲取圖像」 *?你的意思是二進制數據嗎? – Phil

+0

更新了這個問題,希望能夠更清楚一點 –

回答

0

您不必困難太
這很簡單

document.getElementById("myImage").src = document.myform.myinput.value; 
+0

我覺得我需要做一個http.get()來獲取用戶的輸入url來獲取圖像 –