通過PHP將json對象的列拆分爲更多列

Question

如何將此json對象拆分爲3部分idawnser和type？

[{"id":"26","answer":[{"option":"3","text":"HIGH"}],"type":"a"}, 
{"id":"30","answer":[{"option":"3","text":"LOW"}],"type":"b"}, 
{"id":"31","answer":[{"option":"3","text":"LOW"}],"type":"c"}] 

和DB名稱：array表名：user_survey_start JSON列名：survey_answers，這是我的代碼：

 <?php 
    $con=mysqli_connect("localhost","root","","arrayy"); 
    // Check connection 
    if (mysqli_connect_errno()) 
     { 
     echo "Failed to connect to MySQL: " . mysqli_connect_error(); 
     } 
$sql="SELECT `survey_answers` FROM `user_survey_start`"; 

if ($result=mysqli_query($con,$sql)){ 

while ($row = mysqli_fetch_row($result)){ 
} 
mysqli_close($con); 
?> 

Answer 1

嘗試使用json_decode()

<?php 
$sql="SELECT `survey_answers` FROM `user_survey_start`"; 

if ($result=mysqli_query($con,$sql)) 
{ 

while ($row = mysqli_fetch_row($result)) 
{ 

    $json = $row[0]; 
    $jason_array = json_decode($json,true); 
    foreach ($jason_array as $data){ 
     $id[] = $data['id']; 
     $answer[] = $data['answer']; 
     $type[] = $data['type']; 

     // here code to insert/update values to db column 
    } 

    echo implode(',',$id); 
    echo implode(',',$answer); 
    echo implode(',',$type); 
    } 

}